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Tomtit [17]
3 years ago
10

Which statement describes how the graph of the given polynomial would change if the term -3x6 is adde

Mathematics
1 answer:
Lesechka [4]3 years ago
5 0

Given:

Polynomial is 2x^6+9x^5-7x^3-1.

Term -3x^6 is added in the given polynomial.

To find:

The end behavior of new polynomial.

Solution:

Let, P(x)=2x^6+9x^5-7x^3-1.

New polynomial is

f(x)=2x^6+9x^5-7x^3-1+(-3x^6)

f(x)=(2x^6-3x^6)+9x^5-7x^3-1

f(x)=-x^6+9x^5-7x^3-1

Highest power of x is 6 which is even and leading coefficient is negative. So,

f(x)\to -\infty\text{ as }x\to -\infty

f(x)\to -\infty\text{ as }x\to \infty

Both ends of the graph will approach negative infinity.

Therefore, the correct option is A.

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Answer:

3/6, 2/5, 0/5

Step-by-step explanation:

4 0
3 years ago
-4(9z -2)<br> hurrryyyyyyyyyyyyyyyyyyyyyyy
Sergio039 [100]
We will use the distributive property. -4 times 9z=-36z -4 times -2=8 so we have -36z+8 as our answer 
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3 years ago
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URGENT HELP ME PLEASE
Trava [24]

Answer:

(a)\log_3(\dfrac{81}{3})=3

(b)\log_5(\dfrac{625}{25})=2

(c)\log_2(\dfrac{64}{8})=3

(d)\log_4(\dfrac{64}{16})=1

(e)\log_6(36^4)=8

(f)\log(100^3)=6

Step-by-step explanation:

Let as consider the given equations are \log_3(\dfrac{81}{3})=?,\log_5(\dfrac{625}{25})=?,\log_2(\dfrac{64}{8})=?,\log_4(\dfrac{64}{16})=?,\log_6(36^4)=?,\log(100^3)=?.

(a)

\log_3(\dfrac{81}{3})=\log_3(27)

\log_3(\dfrac{81}{3})=\log_3(3^3)

\log_3(\dfrac{81}{3})=3        [\because \log_aa^x=x]

(b)

\log_5(\dfrac{625}{25})=\log_5(25)

\log_5(\dfrac{625}{25})=\log_5(5^2)

\log_5(\dfrac{625}{25})=2        [\because \log_aa^x=x]

(c)

\log_2(\dfrac{64}{8})=\log_2(8)

\log_2(\dfrac{64}{8})=\log_2(2^3)

\log_2(\dfrac{64}{8})=3        [\because \log_aa^x=x]

(d)

\log_4(\dfrac{64}{16})=\log_4(4)

\log_4(\dfrac{64}{16})=1        [\because \log_aa^x=x]

(e)

\log_6(36^4)=\log_6((6^2)^4)

\log_6(36^4)=\log_6(6^8)

\log_6(36^4)=8            [\because \log_aa^x=x]

(f)

\log(100^3)=\log((10^2)^3)

\log(100^3)=\log(10^6)

\log(100^3)=6            [\because \log10^x=x]

5 0
3 years ago
The parabola with equation $y=ax^2+bx+c$ is graphed below:
Mashutka [201]

Answer:

m-n=2

Step-by-step explanation:

Instead of using the standard form, we can use the vertex form of a quadratic equation:

f(x)=a(x-h)^2+k

Where a is the leading coefficient, and (h, k) is our vertex.

Our vertex point is at (2, -4). So, let’s substitute 2 for h and -4 for k:

f(x)=a(x-2)^2-4

Now, we need to determine a.

We know that it passes through the point (4, 12). So, when x is 4, y must be 12. In other words:

12=a((4)-2)^2-4

Solve for a. Subtract within the parentheses:

12=a(2)^2-4

Add 4 to both sides:

16=a(2)^2

Square:

16=4a

Solve:

a=4

Thererfore, the value of a is 4.

So, our function is:

f(x)=4(x-2)^2-4

Now, let’s find our roots. Set the equation to 0 and solve for x:

0=4(x-2)^2-4

4=4(x-2)^2\\1=(x-2)^2\\x-2=\pm1 \\ x=2\pm1 \\ x=3\text{ or } 1

So, our roots are 1 and 3.

The greater root is 3 and the lesser root is 1.

Therefore, m-n, where m>n, is 3-1 or 2.

Our final answer is 2.

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3 years ago
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tom has twice as many marbles as luke. together they have 39 marbles. how many marbles does tom have?
kodGreya [7K]
Tom has 26 marbles. if you need to show your work it would be 13x2= 26 and 26+13=39
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