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Alla [95]
3 years ago
10

What is 5 lb10 oz + 3 lb12 oz

Mathematics
2 answers:
katen-ka-za [31]3 years ago
5 0

5 lb 10 oz + 3 lb 12 oz

5 lb + 3 lb + 10 oz + 12 oz

8 lb + 22 oz

1 lb = 16 oz

22 oz = 1 lb 6 oz

8 lb + (1 lb 6 oz)

9 lb 6 oz

Hope this helps!

yanalaym [24]3 years ago
4 0

Answer:

9 lbs and 6 Oz

Step-by-step explanation:

10 + 12= 22

5+3= 8

1 lbs=16 oz

22-16=6

5+3+1=9

6 oz is left over

Hope this helps :)

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D=6, Dx=-6, Dy=-24, Dz=-30 what is the solution set
Elis [28]

Answer:

  (x, y, z) = (-1, -4, -5)

Step-by-step explanation:

(x, y, z) = (Dx, Dy, Dz)/D = (-6, -24, -30)/6

(x, y, z) = (-1, -4, -5)

3 0
3 years ago
What's the greatest common factor of 52 and 91?
lora16 [44]
13 !!
52/13 = 4
91/13 = 7

Good Day !!
Liaaam66
6 0
3 years ago
Read 2 more answers
x2 + y2 − 4x + 12y − 20 = 0 (x − 6)2 + (y − 4)2 = 56 x2 + y2 + 6x − 8y − 10 = 0 (x − 2)2 + (y + 6)2 = 60 3x2 + 3y2 + 12x + 18y −
snow_tiger [21]
For this case, what we must do is fill squares in all the expressions until we find the correct result.
 We have then:
 
 x2 + y2 − 4x + 12y − 20 = 0 x2 + y2  − 4x + 12y = 20
 x2  − 4x + y2 + 12y = 20
 x2  − 4x + (12/2)^2 + y2 + 12y  + (-4/2)^2 = 20 + (12/2)^2 + (-4/2)^2
 x2  − 4x + (6)^2 + y2 + 12y  + (-2)^2 = 20 + (6)^2 + (-2)^2
 x2  − 4x + 36 + y2 + 12y  + 4 = 20 + 36 + 4
 (x − 2)2 + (y + 6)2 = 60 

 
3x2 + 3y2 + 12x + 18y − 15 = 0 
 
x2 + y2 + 4x + 6y − 5 = 0 
 x2 + y2 + 4x + 6y  = 5 
 x2  + 4x + (4/2)^2 + y2 + 6y + (6/2)^2 = 5 + (4/2)^2 + (6/2)^2 
 x2  + 4x + (2)^2 + y2 + 6y + (3)^2 = 5 + (2)^2 + (3)^2 
 x2  + 4x + 4 + y2 + 6y + 9 = 5 + 4 + 9 
 (x + 2)2 + (y + 3)2 = 18 

 2x2 + 2y2 − 24x − 16y − 8 = 0
 x2 + y2 − 12x − 8y − 4 = 0
 x2 + y2 − 12x − 8y = 4 
 x2 − 12x + (-12/2)^2 + y2 − 8y + (-8/2)^2 = 4 + (-12/2)^2 + (-8/2)^2
 x2 − 12x + (-6)^2 + y2 − 8y + (-4)^2 = 4 + (-6)^2 + (-4)^2
 x2 − 12x + 36 + y2 − 8y + 16 = 4 + 36 + 16
 (x − 6)2 + (y − 4)2 = 56 

 x2 + y2 + 2x − 12y − 9 = 0
 x2 + y2  + 2x - 12y = 9
 x2  + 2x + y2 - 12y = 9
 x2  + 2x + (2/2)^2 + y2 - 12y  + (-12/2)^2 = 9 + (2/2)^2 + (-12/2)^2
 x2  + 2x + (1)^2 + y2 - 12y  + (-6)^2 = 9 + (1)^2 + (-6)^2
 x2  + 2x + 1 + y2 - 12y  + 36 = 9 + 1 + 36
 (x + 1)2 + (y − 6)2 = 46
7 0
3 years ago
How many arrangements can be made using 2 letters of the word HYPERBOLAS if no letter is to be used more than once?
alisha [4.7K]

Answer:

90 arrangements

Step-by-step explanation:

Since there are no repititions of letters, there are unique  10 letters in total.

THe number of arrangements would be 2 permutation 10. We need the formula for permutation. That is:

nPr=\frac{n!}{(n-r)!}\\

Now, n = 10 [total] and r is 2, so we have:

nPr=\frac{n!}{(n-r)!}\\\\_{10}P_{2}=\frac{10!}{(10-2)!}\\=\frac{10!}{8!}\\=\frac{10*9*8!}{8!}\\=10*9\\=90

So, there can be 90 arrangements

3 0
3 years ago
A jacket's original price is 65.00. it is on sale for 40% off. you have to pay 5% sales tax. what is the final price for the jac
nekit [7.7K]
40% of 65.00=0.40×65=26
65-26=39(your price)

sales tax(5%)=0.05×39=1.95 tax

39+1.95
=40.95(total)
3 0
3 years ago
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