Answer:
- After 4 seconds the height is 480 meters.
- The maximum height is 484 meters.
- The ball hits the ground after 10 seconds
Step-by-step explanation:
The height after four seconds is h(4) = -16 * r² + 144*4+160 = 480
The maximum height of the ball is the value it takes at its vertex 'v = -b/2a'. In this case a = -16 and b = 144, so the v = -144/-32 = 4.5. The maximum height of the ball as a result is h(4.5) = -16 (4.5)² + 144*4.5 + 160 = 484
To find the moment the ball hits the ground, we need to find when h takes the value 0 by using the quadratic formula, with a = -16, b = 144 and c = 160.
Since t cant take negative values, then the correct value is 10. The ball hits the ground after 10 seconds.
Answer:
Answer: 3
Step-by-step explanation:
Use BODMAS
<u>Step 1: Open bracket (1 2/5 +3.5÷1 1/4 )</u>
<em>Convert mixed fractions into improper fractions</em>
7/5 + 3.5 ÷ 5/4
<em>Divide 3.5 by 5/4</em>
7/5 + 2.8 = 4.2
<u>Step 2: Carry out all divisions</u>
<em>Convert mixed fraction into improper fractions</em>
4.2 ÷2 2/5 +3.4÷2 1 /8 −0.35
4.2 ÷ 12/5 + 3.4 ÷ 17/8 - 0.35
1.75 + 1.6 - 0.35
<u>Step 3: Solve</u>
1.75 + 1.6 - 0.35
3.35 - 0.35
Answer = 3
Answer:
Rotation, Reflection, Dilation.
Step-by-step explanation:
Answer:
9
Step-by-step explanation:
3^3 is 27 so
27·27/3^4
3^4 is 81 so
27·27/81
27·27 is 729 so
729/81
729÷81 is 9
Answer:
I think that it would be -40
Step-by-step explanation:
I think this because they had to go back 40 spaces because 8 x 5 = 40.
