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Dafna1 [17]
4 years ago
12

If a gas is cooled from 325K to 275K and the volume is constant, what would the final pressure be if it was originally 750mmHg?

Chemistry
1 answer:
salantis [7]4 years ago
3 0

Answer:

635

p/T is a constant

(750/325)×275

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Lime is a term that includes calcium oxide (cao, also called quicklime) and calcium hydroxide (ca(oh)2 also called slaked lime).
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Answer: - 986.6 kj/mol


Explanation:


1) Equation given:


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2) Standard enthalpies of formation given:


CaO, δhf⁰ = −635.6 kj/mol


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3) Calculate the standard enthalpy of formation of Ca(OH)₂.


δh⁰ = ∑δh⁰f of products - ∑ δh⁰f of reactants


Using the mole coefficients of the balanced chemical equation:


δh⁰ = δh⁰f Ca(OH)₂ - δh⁰f CaO - δh⁰f H₂O


⇒ δh⁰f Ca(OH)₂ = δh⁰ + δh⁰f CaO + δh⁰f H₂O


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A gas at 76 K is under a pressure of 78.4 kPa. If the temperature changes to 105 what will be the new
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Answer:

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Explanation:

Given parameters:

Initial temperature  = 76k

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Unknown:

Final or new pressure  = ?

Solution:

To solve this problem, we apply the combined gas law:

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