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LenKa [72]
2 years ago
11

Which observation provides evidence that some kinds of mediums can bend

Chemistry
2 answers:
Lisa [10]2 years ago
6 0

Answer:

im pretty sure its A, if not so sorry!!

Explanation:

Akimi4 [234]2 years ago
3 0

Answer: Its C.

Explanation: Trust me I checked.

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The brightness of a star is determined by _____.
Travka [436]

Answer:

Size and Temperature or E & B

Explanation:

7 0
2 years ago
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Which statement would support a merit of the Bronsted-Lowry base theory has over the Arrhenius base theory?
butalik [34]

Answer:

Explanation:

Bronsted Base is an H+ acceptor

No good answer Bronstead base does not accept hydroxide or electrons

5 0
3 years ago
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Question 6
Gnom [1K]

Answer:

the answers 5, also did u finish ur ia yet,

if so you know what to do.

Explanation:

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3 years ago
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Determine the mass of SO₂ that contains 6.075 × 10^26 S atoms.​
Misha Larkins [42]

Avogadro's law states that in a mole of any substance, there are 6.022 \times 10^{23} atoms. This means that in the given sample, there are

\frac{6.075 \times 10^{26}}{6.022 \times 10^{23}}=1008.8010627 \text{ mol}

  • The atomic mass of sulfur is 32.06 amu.
  • The atomic mass of oxygen is 15.9994 amu.

So, the atomic mass of sulfur dioxide is

32.06+2(15.9994=64.0588 \text{ g/mol}

Therefore, the mass is:

(64.0588)(1008.8010627)=\boxed{64620 \text{ g (to 4 sf)}}

7 0
2 years ago
Calculate ∆G ◦ r for the decomposition of mercury(II) oxide 2 HgO(s) → 2 Hg(ℓ) + O2(g) ∆H◦ f −90.83 − − (kJ · mol−1 ) ∆S ◦ m 70.
bagirrra123 [75]

Answer:

4. +117,1 kJ/mol

Explanation:

ΔG of a reaction is:

ΔGr = ΔHr - TΔSr <em>(1)</em>

For the reaction:

2 HgO(s) → 2 Hg(l) + O₂(g)

ΔHr: 2ΔHf Hg(l) + ΔHf O₂(g) - 2ΔHf HgO(s)

As ΔHf of Hg(l) and ΔHf O₂(g) are 0:

ΔHr: - 2ΔHf HgO(s) = <u><em>181,66 kJ/mol</em></u>

<u><em /></u>

In the same way ΔSr is:

ΔSr= 2ΔS° Hg(l) + ΔS° O₂(g) - 2ΔS° HgO(s)

ΔSr= 2* 76,02J/Kmol + 205,14 J/Kmol - 2*70,19 J/Kmol

ΔSr= 216,8 J/Kmol = <em><u>0,216 kJ/Kmol</u></em>

Thus, ΔGr at 298K is:

ΔGr = 181,66 kJ/mol - 298K*0,216kJ/Kmol

ΔGr = +117,3 kJ/mol ≈ <em>4. +117,1 kJ/mol</em>

<em></em>

I hope it helps!

5 0
3 years ago
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