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3241004551 [841]
3 years ago
11

Which is the equation of a line that has a slope of 5 and passes through point (2, -3)?

Mathematics
1 answer:
saw5 [17]3 years ago
6 0

Answer:

That's the answer I do it this way hope it helps

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What is the slope of a line that is perpendicular to the line that goes through (5,4) and (-2,-3)?
Snowcat [4.5K]

First, let us solve for the slope of the line which it intersects with:

m’ = (y2 – y1) / (x2 – x1)

m’ = (-3 – 4) / (-2 – 5)

m’ = 1

 

The slope of the perpendicular line is the negative reciprocal, therefore:

m = - 1 / m’

m = - 1 / 1

m = -1

 

<span>So the slope of the line is -1.</span>

3 0
3 years ago
7,095 : 62 =<br> Help me I need it
zlopas [31]

Answer:

Your answer to this would be 114.44

It was 114.435, but I round it.

4 0
4 years ago
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The volume of the polyhedron is ______ cm3.
PSYCHO15rus [73]

Answer:

50.80 cm^3

Step-by-step explanation:

the polyhedron is a rectangular pyramid

Volume of a rectangular pyramid = 1/3 x ( width x height x length)

1/3 ( 4 x 5 x 3) = 20 inches

we need to convert inches to cm

1 in = 2.54 cm

20 x 2.54 = 50.80 cm^3

8 0
3 years ago
What is 122.95 rounded to the nearest tenth
katovenus [111]

Answer:

123

Step-by-step explanation:

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3 years ago
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Explain why if a runner completes a 6.26.2​-mi race in 3434 ​min, then he must have been running at exactly 1010 ​mi/hr at least
iren [92.7K]

Answer:

All speed from 0 mi/h and 11 mi/h were reached because the initial and final speed was 0 mi/h the speed of 10 mi/hr was reached at least twice in the race.

Step-by-step explanation:

Given,

Total distance covered = 6.2 miles,

Time taken = 34 minutes = \frac{34}{60} hours

( 1 hour = 60 minutes )

Since,

Speed = \frac{Distance}{Time}

Thus, the speed of the runner = \frac{6.2}{\frac{34}{60}}

=\frac{6.2\times 60}{34}

=\frac{372}{34}

= 10.9411764706

≈ 11 miles per hour

Thus, the average speed of the runner is 11 miles per hour ( approx )

By MVT,

The speed was exactly 10 mi/hr at least twice in the race.

By intermediate value theorem,

All speed from 0 mi/h and 11 mi/h were reached because the initial and final speed was 0 mi/h the speed of 10 mi/hr was reached at least twice in the race.

4 0
3 years ago
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