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4 years ago

11

The viscosities of several liquids are being compared. All the liquids are poured down a slope with equal path lengths. The liqu

id with the highest viscosity will _____.

1 answer:

Marysya12 [62]4 years ago

4 0

Answer:

The liquid with the highest viscosity will reach the bottom last.

Explanation:

Viscosity is the measurement of the liquid or resistance of fluids to flow and it therefore measures its internal friction, as the liquid with high viscosity has its molecular structure gives it a high internal friction when it is moving, so it moves slowly, but the liquid with a lower viscosity has its molecular structure gives it a low internal friction and its resistance to the surface which pass on it is being lower, so it flows faster on the surface.

You might be interested in

explain why for thousands of years people believed that stars moved across Earth's sky. Explain why we now have a different expl

Anarel [89]

Answer:

Ptolemy proposed a model, he reference system is centered on the Earth

Copernicus, proposed a deferent system, this system is centered on the Sun, where it is at the origin of the system

Explanation:

Thousands of years ago, Ptolemy proposed a model to explain the movement of the planets and stars in the sky, in this model the reference system is centered on the Earth, so each body is orbiting in different spheres around the Earth as its center, this system had very complicated calculations and curves to be able to explain the orbits of the planets.

More recently Copernicus, proposed a deferent system, this system is centered on the Sun, where it is at the origin of the system, in this system the movement of the planets are ellipses, which is a much simpler explanation and has been widely accepted, in current systems the reference system is fixed in the bodies more massive, since this simplifies the explanation of the movements.

6 0

3 years ago

the mass of a mineral is 125 g the mineral is placed in a graduated cylinder containing 150.o mL of water. the water level rises

riadik2000 [5.3K]

Answer:

0.71428 g/mL

Explanation:

d = m/v

x = 125/175

solve for x

8 0

3 years ago

What do you think that astronomers mean when they use the term observable universe? (Hint: Think of the time it takes for light

Kryger [21]

What does "observable universe" mean?

Light does not travel instantaneously between points in space. It has a finite speed "c", measured experimentally to be about 3 x 108 meters/second (or about 1.1 x 109 kilometers/hour. Flying at this rate you could get from NYC to Tokyo in about 1/30th of a second.)

Since light takes time to travel, we never actually see the current moment. Looking down at your hand, you do not see it as it is right now, but rather as it was a miniscule fraction of a moment earlier. Now, this interval is so small, given the short distance between your retina and your hand, that the difference is utterly negligible. In fact, bound by Earth's meager scope, the phenomenon isn't really worth mentioning.

The discrepancy becomes significant, however, when exploring much larger distances. Light years, for example. A light year is the distance light travels in one year. If you look at a star that's 50 light years away, you are seeing it as it was 50 years ago. Thus the deeper you peer into space, the farther you are seeing back in time. If this star had exploded 49 years ago, in a spectacular event called a Supernova, we would not know it until 1 more year from now.

Likewise, any event that happened beyond a certain point in the past is unknowable to us if the signal from it hasn't had time to reach us. It is not that our telescopes are too weak, or our instrumentation insensitive. We simply do not yet have access to the information. (No matter how prolific a reader you may be, you'd be hard pressed to read a friend's email if it has yet to arrive in your inbox.)

As a consequence of this limitation, astronomers often refer to the observable universe, a term referring to the volume of space that we are physically able to detect. The question of what lies outside this observable region is a tempting one to ponder. Yet inspiring though it may be, there is a certain futility in such a pursuit.

5 0

3 years ago

Is there anyone good at physics that can help me answer this question. If your not able to answer could you at least show steps

ale4655 [162]

Here's what you need to know about a transformer:

-- The <u><em>ratio</em></u> of voltages is the same as the <u><em>ratio</em></u> of turns.

Say you put 10 volts across one side of the transformer. If the other side has twice as many turns, there'll be (10 x <u>2</u>) = 20 volts across that side. If the other side has half as many turns, then there'll be (10 x <u>1/2</u>) = 5 volts across that side.

-- The <u><em>power</em></u> is the same on both sides. Whatever power goes in, the same power comes out. (It's the amount of energy every second, so it can't be created or destroyed.)

-- Just like every other electrical situation ... <em>Power = (voltage) x (current)</em>

Oh, I should also mention that any time you're working with a transformer, you're working with AC (alternating current). If you put DC into a transformer, the only thing you get out of it is smoke. This question doesn't even mention AC or DC. It's just something to remember about transformers.

= = = = =

So, now, let's see what we've got here:

-- 200 turns on the primary, 50 turns on the secondary. ==> Whatever voltage we put across the primary, we'll get <em>1/4 of that voltage</em> on the secondary.

-- Electric power in the primary = 80 KW. ==> <em>SAME 80 KW</em> in the secondary.

-- 10,000 volts (10 kV) across the primary. ==> <em>2,500 volts</em> across the secondary.

(1). Voltage across the secondary ? 1/4 of the primary voltage

<em>Voltage = 2,500 V</em>

(2). Current through the secondary ? Well, the power has to be the same in both windings = 80,000 watts (80 KW) = (voltage) x (current).

(2,500 V) x (current) = 80,000 watts

Current = (80,000 watts) / (2500 V)

<em>Current = 32 Amperes</em>

(3). What is the resistance, connected to the secondary, that's eating all of this power ?

R = V / I

Resistance = (voltage) / (current)

Resistance = (2500 V) / (32 A)

<em>Resistance = 78.125 ohms</em>

5 0

3 years ago

When the Glen Canyon hydroelectric power plant in Arizona is running at capacity, 690 m3 of water flows through the dam each sec

igomit [66]

Answer:

The maximum electric power output is $P_{max} =1.339*10^{9} \ W$

Explanation:

From the question we are told that

The capacity of the hydroelectric plant is $\frac{V}{t} = 690 \ m^3 /s$

The level at which water is been released is $h = 220 \ m$

The efficiency is $\eta =$ 0.90

The electric power output is mathematically represented as

$P = \frac{PE_l - PE _o}{t}$

Where $PE_l$ is the potential energy at level h which is mathematically evaluated as

$PE_l = mgh$

and $PE_o$ is the potential energy at ground level which is mathematically evaluated as

$PE_o = mg(0)$

$PE_o = 0$

So

$P = \frac{mgh}{t}$

here $m = V * \rho$

where V is volume and $\rho$ is density of water whose value is $\rho = 1000 kg/m^3$

So

$P = \frac{(\rho * V) * gh}{t}$

$P = \frac{V}{t} * gh \rho$

substituting values

$P =690 * 9.8 * 220 * 1000$

$P =1.488*10^{9} \ W$

The maximum possible electric power output is

$P_{max} = P * \eta$

substituting values

$P_{max} =1.488*10^{9} * 0.90$

$P_{max} =1.339*10^{9} \ W$

6 0

3 years ago