All categories

3 years ago

Black holes have three major parts that include:

Physics

2 answers:

marishachu [46]3 years ago

6 0

Answer:

A) The event horizon, singularity, and the chute located between the two.

sveticcg [70]3 years ago

4 0

Answer:

Black holes have three major parts that include A) The event horizon, singularity, and the chute located between the two.

Explanation:

A black hole is a celestial object that has an extremely important mass in a very small volume. They are cold remains of very old stars that contain a lot of matter in a compact space. Because of this, they have a great force of gravity.

Black holes are only formed by very massive stars. When they collapse on themselves forming a well in space: a black hole. If they are not so massive, the matter they are made of can stop the collapse and form a dying star that barely shines: a white dwarf or a neutron star.

Black holes have three main parts that include:

The event horizon: In the center of each black hole there is such a concentration of matter that it exerts a gravitational attraction so strong that not even light, the fastest phenomenon in nature, can escape. Then the event or event horizon is the point at a distance from the center of that rotating celestial object where matter or energy, when crossed, cannot escape gravity.
The singularity: a singularity is a theoretical point with zero volume and infinite density. It is a place where the density of matter and the curvature of space become infinite. They are inside the horizon of a black hole.
The ramp located between the two (the even horizon and singularity).

You might be interested in

What is the displacement current in the capacitor if the potential difference across the capacitor is increasing at 500,000V/s?

konstantin123 [22]

Answer:

$I=2.71\times 10^{-5}\ A$

Explanation:

A 6.0-cm-diameter parallel-plate capacitor has a 0.46 mm gap.

What is the displacement current in the capacitor if the potential difference across the capacitor is increasing at 500,000V/s?

Let given is,

The diameter of a parallel plate capacitor is 6 cm or 0.06 m

Separation between plates, d = 0.046 mm

The potential difference across the capacitor is increasing at 500,000 V/s

We need to find the displacement current in the capacitor. Capacitance for parallel plate capacitor is given by :

$C=\dfrac{A\epsilon_o}{d}\\\\C=\dfrac{\pi r^2\epsilon_o}{d}$ , r is radius

Let I is the displacement current. It is given by :

$I=C\dfrac{dV}{dt}$

Here, $\dfrac{dV}{dt}$ is rate of increasing potential difference

$I=\dfrac{\pi r^2\epsilon_o}{d}\times \dfrac{dV}{dt}\\\\I=\dfrac{\pi (0.03)^2\times 8.85\times 10^{-12}}{0.46\times 10^{-3}}\times 500000\\\\I=2.71\times 10^{-5}\ A$

So, the value of displacement current is $2.71\times 10^{-5}\ A$ .

4 0

3 years ago

A source charge generates an electric field of 4286 N/C at a distance of 2. 5 m. What is the magnitude of the source charge? (Us

svp [43]

The magnitude of the source charge is 3 μC which generates 4286 N/C of the electric field. Option B is correct.

What does Gauss Law state?

It states that the electric flux across any closed surface is directly proportional to the net electric charge enclosed by the surface.

$Q = \dfrac {ER^2}k$

Where,

$E$ = electric force = 4286 N/C

$k$ = Coulomb constant = $8.99 \times 10^9 \rm\ N m ^2 /C ^2$

$Q\\
$ = charges = ?

$r$ = distance of separation = 2.5 m

Put the values in the formula,

$Q = \dfrac {4286\times 2.5 ^2}{8.99 \times 10^9 }\\\\
Q = 3\rm \ \mu C$

Therefore, the magnitude of the source charge is 3 μC.

Learn more about Gauss's law:

brainly.com/question/1249602

8 0

2 years ago

What are four minerals that are commonly taken from ores

Umnica [9.8K]

If it helps or doesn't I'm sorry, but if you even played the game Minecraft just remember it.

Gold, silver, coal, and iron come from ores.

5 0

3 years ago

Which type of reaction does this chemical equation represent? 2Na + MgCl2 - 2NaCl + Mg

Airida [17]

Answer: Single replacement

Explanation: A P E X

5 0

3 years ago

Read 2 more answers

If the current in a wire increases from 5 A to 10 A, what happens to its magnetic field? If the distance of a charged particle f

Anna007 [38]

(1) Doubling of the current through the wire will result in doubling of its magnetic field.

The magnetic field around a wire is a function of the current I and radial distance r

$B = \frac{\mu\cdot I }{2\pi r}$

(with mu denoting the magnetic permeability of the medium). So, B is directly proportional to I. The field magnitude will double with the doubled current from 5A to 10A

(2) Using the same formula as in (1), we can see that the magnetic field is inversely proportional to the radial distance from the wire. So, a particle at 20cm will experience half the magnitude compared to a particle at 10cm.

(3) Answer

If a particle with a charge q moves through a magnetic field B with velocity v, it will be acted on by the magnetic force

$F_m = B\cdot v\cdot q$

So, a particle with charge -2uC will experience a magnetic force of same magnitude but opposite direction (and perpendicular to B) as compared to a particle with a charge of 2uC

3 0

3 years ago

Read 2 more answers