12 6 1/4 pieces can be cut out.
Answer:
maximum height is 4.058 metres
Time in air = 0.033 second
Step-by-step explanation:
Given that the equation height h
h = -212t^2 + 7t + 4
What is the toy's maximum height?
Let us assume that the equation is a perfect parabola
Time t at Maximum height will be
t = -b/2a
Where b = 7 and a = - 212
t = -7/ - 212 ×2
t = 7/ 424 = 0.0165s
Substitute t in the main equation
h = - 212(7/424)^2 + 7(7/424) + 4
h = - 0.05778 + 0.115567 + 4
h = 4.058 metres
Therefore the maximum height is 4.058 metres
How long is the toy in the air?
The object will go up and return to the ground.
At ground level, h = 0
-212t^2 + 7t + 4 = 0
212t^2 - 7t - 4 = 0
You can factorize the above equation and pick the positive time t since time can't be negative
Or
Since we have assumed that it's a perfect parabola,
Total time in air = (-b/2a) × 2
Time in air = 0.0165 × 2 = 0.033 s
Answer:
∡x = 74º
Step-by-step explanation:
∡x= 180º - 106 = 74º
Solution:
we are given that
Both circle Q and circle R have a central angle measuring 140°. The area of circle Q's sector is 25π m^2, and the area of circle R's sector is 49π m^2.
we have been asked to find the ratio of the radius of circle Q to the radius of circle R?
As we know that
Area of the sector is directly proportional to square of radius. So we can write
Answer:
The length of the rectangle is 15 inches and the width is 33 inches
Step-by-step explanation:
The dimensions for the rectangle are as follows:
L=L and W=2L+3
The equation for perimeter of a rectangle is:
P=2l+2w
To Solve:
1. Plug values into perimeter equation
96=2(L)+2(2L+3)
2. Simplify the equation above.
96=2L+4L+6
3. Combine like terms:
96=6L+6
4. Solve for L by subtracting 6 from both sides:
90=6L
5. Solve for L by dividing both sides by 6:
15=L.
6. Plug 15 into the equation for the width:
2(15)+3=w
30+3=w.
