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3 years ago

What is a numerical expression for the verbal expression. eight times six divided by two minus nine

Mathematics

2 answers:

Murljashka [212]3 years ago

8 0

Answer:

(8x6)/2 + 9

Step-by-step explanation:

Ugo [173]3 years ago

3 0

Answer:

Step-by-step explanation:

8×6÷2-9

48÷2-9

24-9

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What is 5x5x5x5? Please answer

Leviafan [203]

Answer:

625

Step-by-step explanation:

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3 years ago

Read 2 more answers

If f is a differentiable function, find an expression for the derivative of each of the following functions

almond37 [142]

12a. Answer: d) x⁶ f'(x) + 6x⁵ f(x)

<u>Step-by-step explanation:</u>

Use the multiplication formula for derivatives:

y = a · b → y' = a'b + ab'

a = x⁶ b = f(x)

a' = 6x⁵ b' = f'(x)

y' = 6x⁵ f(x) + x⁶ f'(x)

***************************************************************

12b. Answer: $\bold{b)\ y=\dfrac{xf'(x)-9f(x)}{x^{10}}'}$

<u>Step-by-step explanation:</u>

Use the division formula for derivatives:

$y=\dfrac{a}{b}$ → $y' = \dfrac{a'b - ab'}{b^2}$

$y=\dfrac{f(x)}{x^9}\\\\a=f(x)\qquad b=x^9\\\\a'=f(x)\qquad b'=9x^8\\\\y'=\dfrac{a'b-ab'}{b^2}\\\\y'=\dfrac{x^9f'(x)-9x^8f(x)}{(x^9)^2}\\\\.\ =\dfrac{x^9f'(x)-9x^8f(x)}{x^{18}}\\\\\text{factor out }x^{8}: y'=\dfrac{xf'(x)-9f(x)}{x^{10}}$

Note: You can also move the denominator to the top (it will have a negative exponent) and use the multiplication formula for derivatives.

5 0

3 years ago

What is the following quotient? StartFraction 3 StartRoot 8 EndRoot Over 4 StartRoot 6 EndRoot EndFraction.

Snowcat [4.5K]

You can simplify the given expression by taking out those factors who are perfect squares.

The simplified form of the given expression will be $\dfrac{\sqrt{3}}{2}$

<h3>How to simplify values which are under the root?</h3>

If possible, try to defactor what is inside the root.

For example, if 8 is under square root, then you can defactor 8 as made up of 2 times 2 times 2. Since 2 times 2 is perfect square, thus this can come out of the root.

Simply, some more such methods can be used to simplify these type of values.

<h3>Using the simplification method on given expression</h3>

$\dfrac{3\sqrt{8}}{4\sqrt{6}} = \dfrac{3\sqrt{2 \times 2 \times 2}}{4\sqrt{6}}\\\\
\dfrac{3\sqrt{8}}{4\sqrt{6}} = \dfrac{3 \times 2\sqrt{2}}{4\sqrt{6}}\\

\\
\dfrac{3\sqrt{8}}{4\sqrt{6}} = \dfrac{6\sqrt{2}}{4\sqrt{6}} = \dfrac{\sqrt{6}\sqrt{2}}{4}\\\\
\dfrac{3\sqrt{8}}{4\sqrt{6}} = \dfrac{\sqrt{12}}{4} = \dfrac{\sqrt{4 \times 3}}{4} = \dfrac{\sqrt{3}}{2}$

Thus, after getting simplified, the expression becomes $\dfrac{\sqrt{3}}{2}$

Learn more about quotient here:

brainly.com/question/16076853

7 0

2 years ago

3[(11-6) 2 squared divided by5]

Studentka2010 [4]

12 use a calculator i did it

8 0

3 years ago

The price elasticity of demand for good X is half the price elasticity of Good Y. A 20% rise in the price of good X results in a

Keith_Richards [23]

The answer is

60% rise in quantity demanded of good x.

Explanation:

Percentage change in quantity demanded for good Y:

= (Change in Quantity ÷ Initial Quantity) × 100

= (60 units ÷ 400 units) × 100

= 15%

Percentage change in price of good Y = 10% Rise

Therefore, the price elasticity of demand for Good Y is as follows:

= Percentage change in Quantity demanded ÷ Percentage change in price

= 15 ÷ 10

= 1.5

Hence,

Price elasticity of demand of good x:

= 2 × price elasticity of demand of good y

= 2 × 1.5

= 3

Percentage change in price of good x:

= (Change in price ÷ Initial price) × 100

= (2 ÷ 10) × 100

= 20%

Therefore,

Price elasticity of demand for Good x = Percentage change in Quantity demanded ÷ Percentage change in price

3 = Percentage change in Quantity demanded ÷ 20

3 × 20 = Percentage change in Quantity demanded

60% = Percentage change in Quantity demanded for good x

Hence, 60% rise in quantity demanded of good x.

7 0

3 years ago