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Brut [27]
3 years ago
8

This diagram of a rectangular city park was drawn using a scale of 1 centimeter to 20 meters

Mathematics
1 answer:
I am Lyosha [343]3 years ago
7 0

Answer:

Scale factor for the drawing from actual park = \frac{1}{20}

Area of the actual park = 1200 cm²

Step-by-step explanation:

Length of the rectangular city park = 5 cm

Width of the rectangular park = 6 cm

Using scale factor 1 cm = 20 meters

Scale factor = \frac{\text{length of the park in drawing}}{\text{Actual length of park}}=\frac{1}{20}

\frac{5}{\text{Actual length of park}}=\frac{1}{20}

Actual length = 5 × 20 = 100 meters

Actual width = 6 × 20 = 120 meters

Area of the rectangular park = length × width

                                               = 100 × 120

                                               = 1200 square meters

Therefore, Scale factor from actual length to the length in drawing = 1 : 20

Area of the rectangular park = 1200 square feet

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Andre45 [30]

Answer:

1. Pour the mixture through a filter to separate the sand; 2. Evaporate the liquid to separate the salt.

Step-by-step explanation:

6 0
3 years ago
Match the inequality to the graph of its solution.<br> a. n/4 ≤ -1<br> b. -10 ≥ -100<br> c. 5x ≥ 20
postnew [5]
<span>a. n/4 ≤ -1

Multiply both sides by 4 => n ≤ - 4, which is all the real numbers less or equal than - 4.

That in the real number line is all the numbers to the left of - 4 (including  -4)

The matching graph is the B.


b. -10n ≥ -100

Divide both sides by - 10 => n ≤ 10

That is all the real numbers less or equal than 10.

In the real number line it is all the numbers to the left of 10, including 10.

So, the matching graph is the A.


c. 5x ≥ 20

Divide both sides by 5 => x ≥ 4

That is all the real numbers greater or equal to 4.

In the real number line it is all the numbers to the right of 4, including 4.

The matching graph is C.</span>
4 0
3 years ago
1. 112<br><br> 2. 136 <br><br> 3. 68 <br><br> 4. 158 <br><br> 5. 129
RideAnS [48]

Answer:

4. 158

Step-by-step explanation:

First let's make things a little simpler and put these arcs in terms of x.  We know that the degree measure around the outside of a circle, regardless of its size, is 360.  So let's say that arc BC is x.  That means that arc BDC is 360 - x.  This is because arc BC + arc BDC = 360.  Substituting in our x's we have:

x + 360 - x = 360 and

360 = 360.  (That's just the proof that putting in our x's as we did does in fact work!)

Following the formula then, we have

22=\frac{1}{2}(360-x-x) and

22=\frac{1}{2}(360-2x)

Multiply both sides by 2 to get rid of the fraction and get

44 = 360 - 2x

Subtract 360 rom both sides to get

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Divide both sides by -2 to get that x = 158

Since we are looking for arc BC and we designated arc BC as our x, that means that arc BC = 158.

3 0
4 years ago
Given z1 and z2 below. Calculate z1/z2 and write your answer in rcistheta form.
andre [41]

Answer:

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Step-by-step explanation:

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  ∠z1 = arctan((3√3)/(-3)) = -arctan(√3) = 120°

  z2 = 27∠90°

So, the ratio is ...

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3 years ago
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