Answer:
The answer is D
Step-by-step explanation:
I solved this with graphing and got d trust me
pls mark brainliest
The answer is: z² .
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Given: <span>(x÷(y÷z))÷((x÷y)÷z) ; without any specified values for the variables;
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we shall simplify.
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We have:
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</span>(x÷(y÷z)) / ((x÷y)÷z) .
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Start with the first term; or, "numerator": (x÷(y÷z)) ;
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x ÷ (y / z) = (x / 1) * (z / y) = (x * z) / (1 *y) = [(xz) / y ]
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Then, take the second term; or "denominator":
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((x ÷ y) ÷z ) = (x / y) / z = (x / y) * (1 / z) = (x *1) / (y *z) = [x / (zy)]
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So (x÷(y÷z)) / ((x÷y)÷z) = (x÷(y÷z)) ÷ ((x÷y)÷z) =
[(xz) / y ] ÷ [x / (zy)] = [(xz) / y ] / [x / (zy)] =
[(xz) / y ] * [(zy) / x] ;
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The 2 (two) z's "cancel out" to "1" ; and
The 2 (two) y's = "cancel out" to "1" ;
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And we are left with: z * z = z² . The answer is: z² .
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Answer:
Function A has the greater initial value because the initial value for Function A is 6 and the initial value for Function B is 3.
Step-by-step explanation:
✔️Function A:
Initial value = y-intercept (b)
y-intercept is the value of y, when the corresponding value of x = 0
From the table, y = 6 when x = 0.
The y-intercept of function A = 6
Therefore, initial value for Function A = 6
✔️Function B:
y = 4x + 3 is given in the slope-intercept form, y = mx + b.
b = y-intercept = initial value.
Therefore
Initial value for Function B = 3
✔️Function A has the greater initial value because the initial value for Function A is 6 and the initial value for Function B is 3.
Answer is True. We cannot write it in rational form where both numbers are finite integers. In this case we cannot represent this number as fraction of finite integers therefore it is irrational.
Answer:
Option B
Step-by-step explanation:
Complex roots occur as conjugate pairs so the third root is -3 - i ( note that the sign changes from + to -).
So in factor form we have:-
(x - 2)(x - (-3 + i))(x - (-3 - i)) = 0 Let's expand the last 2 factors first:-
(x - (-3 + i))(x - (-3 - i))
= (x + 3 - i)(x + 3 + i)
= x^2 + 3x +ix + 3x + 9 + 3i - ix - 3i - i^2
= x^2 + 6x + 9 - (-1)
= x^2 + 6x + 10
Now multiplying by (x - 2):-
(x - 2)(x^2 + 6x + 10) = 0
x^3 + 6x^2 + 10x - 2x^2 - 12x - 20 = 0
x^3 + 4x^2 - 2x - 20 = 0 (answer)
Option B
