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Fudgin [204]
3 years ago
8

You are 2.4 m from a plane mirror, and you would like to take a picture of yourself in the mirror. You need to manually adjust t

he focus of the camera by dialing in the distance to what you are photographing. What distance do you dial in
Physics
1 answer:
sveticcg [70]3 years ago
7 0

Answer:

4.8 m

Explanation:

A mirror is a reflecting surface on which rays of light are reflected. Reflection occurs when a ray of light bounces off a surface, coming back into the original medium.

There exists two types of mirrors:

- Flat mirrors: they consist of a flat surface

- Curved mirrors: they consist of curved surfaces. They are further divided into convex mirrors and concave mirrors.

For a flat mirror, the image produced from the mirror is always:

- Virtual (on the other side of the mirror)

- Of the same size as the object

- Laterally inverted

- Upright (same orientation as the object)

Moreover, the image produced by a flat mirror is at the  same distance from the mirror as the object.

So in this case, since the person is 2.4 m from the mirror, then the image is produced 2.4 m from the mirror (but on the other side).

This means that the total distance between you and your image in the mirror is:

d = 2.4 + 2.4 = 4.8 m

Therefore, the focus of the camera must be adjusted to be at 4.8 m.

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Hannah walks 0.30 km to class in 5.0 min. what is her average speed in m/s?
OverLord2011 [107]

Answer:

1.0 m/s

Explanation:

First, convert to SI units.

0.30 km × (1000 m / km) = 300 m

5.0 min × (60 s / min) = 300 s

Speed is distance divided by time:

300 m / 300 s = 1.0 m/s

3 0
3 years ago
A football kicker kicks a ball with a mass of .42 kg. The average acceleration of the football was 14.8 m/s squared. How much fo
mrs_skeptik [129]

To find the force we use the formula,

F = ma , where m is mass and a acceleration

Using the formula,

F = ma

F = 0.42 x 14.8

F = 6.216 N / 6.22 N

Hope you liked the answer !

4 0
3 years ago
If two opposing forces are equal, then the net force is 0 N.<br><br> true or false?
Fofino [41]

Answer:

false

Explanation:

6 0
3 years ago
How much work would it take to push two protons very slowly from a separation of 2.00×10−10m (a typical atomic distance) to 3.00
laiz [17]

Answer:

Work= -7.68×10⁻¹⁴J

Explanation:

Given data

q₁=q₂=1.6×10⁻¹⁹C

r₁=2.00×10⁻¹⁰m

r₂=3.00×10⁻¹⁵m

To find

Work

Solution

The work done on the charge is equal to difference in potential energy

W=ΔU

Work=U_{1}-U_{2}\\ Work=-kq_{1}q_{2}[\frac{1}{r_{2}}-\frac{1}{r_{1}} ]\\Work=(-9*10^{9})*(1.6*10^{-19} )^{2}[\frac{1}{3.0*10^{-15} }-\frac{1}{2*10^{-10} } ]\\  Work=-7.68*10^{-14}J

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4 years ago
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qwelly [4]
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4 years ago
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