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Fudgin [204]
3 years ago
8

You are 2.4 m from a plane mirror, and you would like to take a picture of yourself in the mirror. You need to manually adjust t

he focus of the camera by dialing in the distance to what you are photographing. What distance do you dial in
Physics
1 answer:
sveticcg [70]3 years ago
7 0

Answer:

4.8 m

Explanation:

A mirror is a reflecting surface on which rays of light are reflected. Reflection occurs when a ray of light bounces off a surface, coming back into the original medium.

There exists two types of mirrors:

- Flat mirrors: they consist of a flat surface

- Curved mirrors: they consist of curved surfaces. They are further divided into convex mirrors and concave mirrors.

For a flat mirror, the image produced from the mirror is always:

- Virtual (on the other side of the mirror)

- Of the same size as the object

- Laterally inverted

- Upright (same orientation as the object)

Moreover, the image produced by a flat mirror is at the  same distance from the mirror as the object.

So in this case, since the person is 2.4 m from the mirror, then the image is produced 2.4 m from the mirror (but on the other side).

This means that the total distance between you and your image in the mirror is:

d = 2.4 + 2.4 = 4.8 m

Therefore, the focus of the camera must be adjusted to be at 4.8 m.

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Answer:

b. more rapidly in the vertical direction

Explanation:

Atmospheric Pressure decreases with increasing altitude. The pressure at any level in the atmosphere may be interpreted as the total weight of the air above a unit area at any elevation.

Pressure decreases with increasing altitude because at higher altitudes both the height of overlying air column and its density decreases. Hence the answer.

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3 years ago
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A frictionless pulley system connects a 150 Kg block of a flat surface with a coefficient of friction of 0.20 to a hanging 200 k
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How does surface type affect speed?​
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2 years ago
a sprinter starts from rest and accelerates at a rate of 0.16 ms ^-2 over a distance of 50.0 meters . How fast is the athlete tr
vlada-n [284]

Answer:

Final velocity v = 4 m/s

Explanation:

Given:

Initial velocity u = 0 m/s

Acceleration a = 0.16 m/s²

Distance s = 50 m

Find:

Final velocity v

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Using; v² = u² + 2as

v² = (0)² + 2(0.16)(50)

v² = 16 m/s

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7 0
3 years ago
An athlete performing a long jump leaves the ground at a 27.0 degree angle and lands 7.80m away. What was the takeoff speed?
Dima020 [189]

Answer:

=9.72 m/s

Explanation:

From the Newton's laws of motion;

x=2(v²cos∅sin∅)/g

Using geometry we see that 2 cos∅sin∅ = sin 2∅

Therefore, x= (v²sin 2∅)g,  where v is the take off speed x the range and ∅ the launch angle.

Making v the subject of the formula we obtain the following equation.

v=√{xg /(sin 2∅)}

x=7.80

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v=√{7.8×9.8/sin(27×2)}

v=√94.485

v=9.72 m/s

3 0
3 years ago
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