Answer:The gravitational force is defined in Uniform Circular Motion and Gravitation, electric force in Electric Charge and Electric Field, magnetic force in Magnetism, and nuclear forces in Radioactivity and Nuclear Physics. On a macroscopic scale, electromagnetism and gravity are the basis for all forces.
Explanation:
Answer:
v = 5.949 m / s
, a = 59.18 m / s²
Explanation:
Linear and angular quantities are related
v = w r
we search the magnitudes to the SI system
w = 95 rev / min (2π rad / 1rev) (1 min / 60 s) = 9.948 rad / s
d = 598 mm = 0.598 m
a) let's calculate the linear velocity
v = 9.948 0.598
v = 5.949 m / s
b) Cenripetal acceleration
a = v² / r
a = 5.94 2 / 0.598
a = 59.18 m / s²
Answer:
2. depends on both the wavelength and frequency of light.
Explanation: Speed of light(v)=wavelength×Frequency.
∴speed of light depends on both wavelength and frequency as shown from the equation above.
As our story begins, the sled ... whose mass is 8 kg ... is sliding along the ice at a speed of 4 m/s.
The sled's kinetic energy is (1/2 m v²) = (4 kg · 16 m²/s²) = 64 J .
After what seems like only the blink of an eye, the sled is no longer sliding. It is stationary. Motionless. At Rest. Just sitting there !
Its speed has been reduced to zero and ... because kinetic energy is the energy of motion ... the sled's kinetic energy is now also zero. Sixty-four Joules of energy have disappeared !
How can this be ? ! ? We know that energy is conserved. It can never just appear out of nothing, and it can never just disappear into nothing. If energy suddenly appears, it had to come from somewhere, and if energy suddenly disappears, it had to go somewhere. So where did our 64 Joules of kinetic energy go ?
It went into the ice, THAT's where ! We can say that the sled did 64J of work, and melted a thin slick layer of water on the surface of the ice. OR we can say that friction did NEGATIVE 64J of work on the sled, to cancel the 64J that it had originally, sap its kinetic energy, and bring it to rest.
I think <em>choice-B</em> was supposed to say "<em>B. -64J</em>", but somebody typed it sloppily and neglected to proofread it before posting.
Answer:
The induced current in the coil at the time 2 s is 0.00263 A
Explanation:
The equation for induced emf is equal to:
Where
B = magnetic field
A = area
θ = angle
For t = 2 s
The induced current is:
