Answer:
2.55 seconds
Explanation:
Given that,
The initial speed of a projectile, u = 21.8 m/s
The angle of projection,
We need to find the time of flight of the projectile. The formula for the time of flight is given by :
Where
g is the acceleration due to gravity
So, the time of flight of the projectile is 2.55 seconds.
Answer:
Orbital period of the planet will be 207.06 year
Explanation:
We have given the planet have the semi major axis as 35 au
We have to find the orbital period of the planet
From Keplar's third law there is relation between the orbital period and semi major axis which is t
So
So orbital period of the planet will be 207.06 year
The Energy flux from Star B is 16 times of the energy flux from Star A.
We have Two stars - A and B with 4900 k and 9900 k surface temperatures.
We have to determine how many times larger is the energy flux from Star B compared to the energy flux from Star A.
<h3>State Stephen's Law?</h3>Stephens law states that if E is the energy radiated away from the star in the form of electromagnetic radiation, T is the surface temperature of the star, and σ is a constant known as the Stephan-Boltzmann constant then-
Now -
Energy emitted per unit surface area of Star is called Energy flux. Let us denote it by E. Then -
Now -
For Star A →
= 4900 K
For Star B →
= 9900 K
Therefore -
2.02 = 2 (Approx.)
Now -
Assume that the energy flux of Star A is E(A) and that of Star B is E(B). Then -
E(B) = E(A) x
E(B) = E(A) x
E(B) = 16 E(A)
Hence, the Energy flux from Star B is 16 times of the energy flux from Star A.
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