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Inessa [10]
3 years ago
5

A projectile is launched with an initial speed of 21.8 m/s at an angle of 35º above the horizontal. Determine the time of flight

of the projectile.
Physics
1 answer:
katrin2010 [14]3 years ago
8 0

Answer:

2.55 seconds

Explanation:

Given that,

The initial speed of a projectile, u = 21.8 m/s

The angle of projection, \theta=35^{\circ}

We need to find the time of flight of the projectile. The formula for the time of flight is given by :

T=\dfrac{2u\sin\theta}{g}

Where

g is the acceleration due to gravity

T=\dfrac{2\times 21.8\sin(35)}{9.8}\\\\T=2.55\ s

So, the time of flight of the projectile is 2.55 seconds.

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a)
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Two charged point particle are located at two vertices of an equilateral triangle and the electric field is zero at the third ve
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Answer:

Option E

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my choice1A child pushes a toy truck up an inclined plane. The lifting force is...Select one:ut ofO a. the weight of the truck.O
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SpyIntel [72]

Based on the forces acting on the axes, the resultant moments will be (345, 400, 600 N·m)

<h3>What would be resultant moment about x-axis?</h3>

= F₃ x 3

= -115 x 3

= -345 N·m

<h3>What would be resultant moment about y-axis?</h3>

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<h3>What would be the resultant moment about z-axis?</h3>

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In conclusion, the resultant moment about x, y, and z axes is (345, 400, 600 N·m)

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