Question

A projectile is launched with an initial speed of 21.8 m/s at an angle of 35º above the horizontal. Determine the time of flight of the projectile.

Answer 1

Answer:

2.55 seconds

Explanation:

Given that,

The initial speed of a projectile, u = 21.8 m/s

The angle of projection, $\theta=35^{\circ}$

We need to find the time of flight of the projectile. The formula for the time of flight is given by :

$T=\dfrac{2u\sin\theta}{g}$

Where

g is the acceleration due to gravity

$T=\dfrac{2\times 21.8\sin(35)}{9.8}\\\\T=2.55\ s$

So, the time of flight of the projectile is 2.55 seconds.