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Inessa [10]
3 years ago
5

A projectile is launched with an initial speed of 21.8 m/s at an angle of 35º above the horizontal. Determine the time of flight

of the projectile.
Physics
1 answer:
katrin2010 [14]3 years ago
8 0

Answer:

2.55 seconds

Explanation:

Given that,

The initial speed of a projectile, u = 21.8 m/s

The angle of projection, \theta=35^{\circ}

We need to find the time of flight of the projectile. The formula for the time of flight is given by :

T=\dfrac{2u\sin\theta}{g}

Where

g is the acceleration due to gravity

T=\dfrac{2\times 21.8\sin(35)}{9.8}\\\\T=2.55\ s

So, the time of flight of the projectile is 2.55 seconds.

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