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3 years ago

Expand the equation (p+q)^5

1 answer:

7 0

(p + q)⁵
(p + q)(p + q)(p + q)(p + q)(p + q)
{[p(p + q) + q(p + q)][p(p + q) + q(p + q)](p + q)}
{[p(p) + p(q) + q(p) + q(q)][p(p) + p(q) + q(p) + q(q)](p + q)}
(p² + pq + pq + q²)(p² + pq + pq + q²)(p + q)
(p² + 2pq + q²)(p² + 2pq + q²)(p + q)
{[p²(p² + 2pq + q²) + 2pq(p² + 2pq + q²) + q²(p² + 2pq + q²)](p + q)}
{[p²(p²) + p²(2pq) + p²(q²) + 2pq(p²) + 2pq(2pq) + 2pq(q²) + q²(p²) + q²(2pq) + q²(q²)](p + q)}
(p⁴ + 2p³q + p²q² + 2p³q + 4p²q² + 2pq³ + p²q² + 2pq³ + q⁴)(p + q)
(p⁴ + 2p³q + 2p³q + p²q² + 4p²q² + p²q² + 2pq³ + 2pq³ + q⁴)(p + q)
(p⁴ + 4p³q + 6p²q² + 4pq³ + q⁴)(p + q)
p⁴(p + q) + 4p³q(p + q) + 6p²q²(p + q) + 4pq³(p + q) + q⁴(p + q)
p⁴(p)+ p⁴(q) + 4p³q(p) + 4p³q(q) + 6p²q²(p) + 6p²q²(q) + 4pq³(p) + 4pq³(q) + q⁴(p) + q⁴(q)
p⁵ + p⁴q + 4p⁴q + 4p³q² + 6p³q² + 6p²q³ + 4p²q³ + 4pq⁴ + pq⁴ + q⁵
p⁵ + 5p⁴q + 10p³q² + 10p²q³ + 5pq⁴ + q⁵

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Complete the equations with powers of 101010. 720{,}800 \div {}720,800÷720, comma, 800, divided by =7.208=7.208equals, 7, point,

jarptica [38.1K]

Answer:

Step-by-step explanation:

Given the expression $\frac{720,800}{x} = 7.208$ , we are to find the value of with powers of 10.

From the equation:

$\frac{720,800}{x} = 7.208$

cross multiply

$720,800 = 7.208x\\7.208x = 720,800$

divide both sides by 7.208

$\frac{7.208x}{7.208} = \frac{720,800}{7.208} \\x = 100,000$

express x in powers of 10

$x = 10 * 10 * 10 * 10* 10\\x = 10^5$

Similarly given the equation $\frac{720,800}{y} = 72.08$

From the equation:

$\frac{720,800}{x} = 72.08$

cross multiply

$720,800 = 72.08x\\72.08x = 720,800$

divide both sides by 7.208

$\frac{72.08x}{72.08} = \frac{720,800}{72.08} \\x = 10,000$

express x in powers of 10

$x = 10 * 10 * 10 * 10\\x = 10^4$

For the equation $\frac{720,800}{z} = 720.8$

From the equation:

$\frac{720,800}{z} = 720.8$

cross multiply

$720,800 = 720.8z\\720.8z = 720,800$

divide both sides by 7.208

$\frac{72.08z}{720.8} = \frac{720,800}{720.8} \\z = 1,000$

express x in powers of 10

$z = 10 * 10 * 10\\z = 10^3$

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2 years ago

) a rectangular box has length 12 inches, width 20 inches, and a height of 7 inches. find the angle between the diagonal of the

nlexa [21]

We assume the base is 12 in × 20 in, so its diagonal has length

... √(12² +20²) = √(144 +400) = √544 = 4√34 . . . inches

Then the tangent of the angle of interest is the ratio of the box height to the base diagonal:

... tan(α) = (7 in)/(4√34 in) ≈ 0.300123

The angle will be the arctangent of this value,

... α = arctan(7/√544) ≈ 0.291569 radians

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3 years ago

Jonathan makes a weekly allowance of $25. He also makes $9.50 an hour at his job. Because of his age, he can work no more than 2

Molodets [167]

C. Normally when you are talking about money and how much he makes an hour plus allowance they want you to draw a graph so C is your answer.

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2 years ago

klio [65]

Answer:

Step-by-step explanation:

red hat, black shirt, black pants

red hat, white shirt, black pants

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black hat, black shirt, black pants

black hat, white shirt, black pants

black hat, striped shirt, black pants

that is six different combinations without the use of the pair of blue pants, thus you should be able to just do all those combinations over again with just blue pants leading to a total of 12 combinations. I think lol

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3 years ago

Help ASAP please ...

cupoosta [38]

Answer:

Angle Q

Step-by-step explanation:

As I said on my previous posts, all you need to remember is CPCTC (corresponding parts of congruent triangles are congruent)

Q corresponds to B, and is thus congruent

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2 years ago

Read 2 more answers