Answer:
Zeros to the left of a decimal can be insignificant place holders, such as in 0.043 (two significant figures).
They can be significant if they are between two digits who themselves are significant, such as in 101.000 (three significant figures).
In the case of a number like 1,000 we can see there is only one significant figure. The zero digits are not between sigfigs.
<span>motion of truck constitutes of 3 travels.
1. accelerating uniformly with acceleration a1 = 2 m/s^2 until its velocity reached 20 m/s travelling a
distance of 's1' meters.
2. uniform motion with 20 m/s for a time duration t1 = 20s travelling a distance of 's2' meters.
3. uniform deceleration for t2 = 5 sec which stops the truck after travelling a distance of 's3' meters.. </span>
Answer: v= 160ft/s
a=32ft/s^2 constant
Explanation:
s(t)=400-16t^2 derivative of position is velocity v(t) and derivative of velocity is acceleration a(t) so let s(t)=0 to find the time of flight to reach the ground and take the two derivatives and use the time found and solve. Also acceleration is a constant as it’s gravity.
0=400-16t^2
400=16t^2
25=t^2
t=5s
ds/dt=v(t)=0-32t
dv/dt=a(t)=-32 constant(gravity)
v(t)=-32(5s)= -160ft/s negative sign is only showing direction
Answer:
Weight is a consequence of the universal law of gravitation
Explanation:
Weight, gravitational force of attraction on an object, caused by the presence of a massive second object, such as the Earth or Moon. Weight is a consequence of the universal law of gravitation: any two objects, because of their masses, attract each other with a force that is directly proportional to the product of their masses and inversely proportional to the square of the distance between them.
The velocity of the speeder is expressed by the equation:
v1 = d1 / t1 --> d1 = v1 t1
And for the police:
d2= v2i t2 + 0.5 a2 t2^2
where v is final velocity, vi is initial velocity, d is
distance, a is acceleration and t is time
The distance of the two must be equal when the police
overtakes the speeder hence:
v1 t1 = v2i t2 + 0.5 a2 t2^2
t1 = t2 = t and v2i = 0 since the police starts at rest,
so:
26.8 t = 0.5 * 2.4 * t^2
26.8 = 1.2 t
<span>t = 22.33 seconds</span>
