All categories

4 years ago

How many total atoms are in one molecule of lithium nitrate, LiNO3? 1 3 5 7 6

Physics

2 answers:

Elan Coil [88]4 years ago

8 0

Answer:

The total atoms in this compound is 5.

Explanation:

Given that,

LiNO₃

Element : Element is the substance whose atoms have a number of protons.

Elements can not be broke using the chemical reaction.

Eg : Lithium (Li)

Compound : Compound is a substance which is the combination of two or more element.The atoms of different elements are held together by chemical bond.

The smallest unit of compound is molecule.

Ex : Nitrate(NO₃)

In this compound, one atom of lithium, one atom of nitrate and three atom of oxygen.

Hence, The total atoms in this compound is 5.

Zanzabum4 years ago

7 0

There are 5 atoms 1=LI 1=N 3=O

You might be interested in

Determine the magnitude and direction of the force on a 200 m power line carrying a current of 5.0-A due west in a magnetic fiel

bogdanovich [222]

Answer:

Explanation:

l = 200 m

i = 5 A west

B = 6 micro Tesla direction 30 degree north of east

angle between length vector and the magnetic field vector = 180 - 30 = 150 degree

Write the length and the magnetic field in the vector form

$\overrightarrow{l}=- 200 \widehat{i}metre$

$\overrightarrow{B}= 6\times 10^{-6}\left ( Cos30\widehat{i}+Sin30\widehat{j} \right )Tesla$

$\overrightarrow{B}=\left ( 5.2\widehat{i}+3\widehat{j} \right )\times 10^{-6}Tesla$

$\overrightarrow{F} = i \overrightarrow{l}\times \overrightarrow{B}$

$\overrightarrow{F} = 5\times \left ( -200\widehat{i} \right )\times \left ( 5.2\widehat{i}+3\widehat{j} \right )\times 10^{-6}$

$\overrightarrow{F} =- 3\times 10^{-3}\widehat{k}Newton$

Thus, the magnitude of force is 3 x 10^-3 newton and it is directed towards negative z axis direction.

7 0

3 years ago

Match the sentences in Column A based on whether they describe radio waves, visible light waves, or both (Column B). Column A 1.

Andrew [12]

1. They’re invisible - RADIO WAVES

2. They have colors. - VISIBLE LIGHT WAVES

3. They’re used to learn about dust and gas clouds. - BOTH

4. They can travel in a vacuum. - BOTH

5. They’re used to find the temperature of stars. - VISIBLE LIGHT WAVES

6. They have energy. - BOTH

8 0

3 years ago

Read 2 more answers

Credit-Card Magnetic Strips Experiments carried out on the television show Mythbusters determined that a magnetic field of 1000

Readme [11.4K]

Answer:

14 μm

Explanation:

The magnetic field due to a long straight wire is B = μ₀i/2πr where μ₀ = permeability of free space = 4π × 10⁻⁷ H/m, i = current = 7.0 A and r = distance of credit card from magnetic field.

So r = μ₀i/2πB since B = 1000 gauss = 1000 G × 1 T/10000 G = 0.1 T

r = 4π × 10⁻⁷ H/m × 7.0 A/(2π × 0.1 T)

r = 2 × 10⁻⁷ H/m × 7.0 A/0.1 T

r = 14 × 10⁻⁷ H/m × A/0.1 T

r = 140 × 10⁻⁷ m

r = 1.4 × 10⁻⁵ m

r = 14 × 10⁻⁶ m

r = 14 μm

4 0

3 years ago

A 10 cm long tensile specimen with a yield stress of 350 MPa is pull to a stress of 300 MPa and then the load is released. What

Advocard [28]

Answer:

The length of the specimen after the load is released is 11.67 cm

Explanation:

Given;

yield stress, Y = 350 MPa

ultimate tensile stress, T = 300 MPa

Elongation factor, e = yield stress, Y / ultimate tensile stress, T

Elongation factor, e = 350 Mpa / 300 Mpa

Elongation factor, e = 1.1667

New length of the specimen = 1.1667 x 10 cm = 11.67 cm

Therefore, when the load is released from 10 cm long tensile specimen, the length of the specimen becomes 11.67 cm

3 0

4 years ago

A 2578-kg van runs into the back of a 825-kg compact car at rest. They move off together at 8.5 m/s. Assuming the friction with

allochka39001 [22]

Answer:

The initial speed of the car = 11.22 m/s

Explanation:

Law of conservation of energy: It states that when two bodied collide in a closed system, the sum of momentum before collision is equal to the sum of momentum after collision.

Note: A close system is one that is free from from external forces. E.g Frictional force.

From the law of conservation of momentum,

Total momentum before collision = Total momentum after collision.

m₁u₁ + m₂u₂ = (m₁ + m₂)V..................... Equation 1

Where m₁ = mass of the van, m₂ = mass of the car, u₁ = initial velocity of the van, u₂ = initial velocity of the car, V = Common velocity.

Given: m₁ = 2578 kg, m₂ = 825 kg, u₂ = 0 ( the car was at rest), V= 8.5 m/s

Substituting these values into equation 1, and solving for u₁

2578(u₁) + (825 × 0) = (2578 + 825)8.5

2578u₁ = 28925.5

Dividing both side of the equation by the coefficient of u₁

2578u₁/2578 = 28925.5/2578

u₁ = 11.22 m/s

The initial speed of the car = 11.22 m/s

3 0

3 years ago