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3 years ago

General Circulation Models (GCM) :_________

Physics

1 answer:

enot [183]3 years ago

3 0

Answer:

Explanation:

GCMs (general circulation models) are useful instruments for gaining a quantitative knowledge of climate processes. Physical processes in the atmosphere, cryosphere, and land surface are represented by them. They are used for modeling the global climate system's reaction to rising greenhouse gas concentrations available at the moment by utilizing spectral models based on the energy emitted by the biosphere and clouds.

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Please help me guys never mind the calculations

vlada-n [284]

The shape is connected in parallel so;

5.1) Ans;

$\frac{1}{R} = \frac{1}{R1} + \frac{1}{R2} \\ \frac{1}{R} = \frac{1}{2} + \frac{1}{3} \\ \frac{1}{R} = \frac{3 + 2}{6} = \frac{5}{6} \\ R = \frac{6}{5} = 1.2 \: \: ohm$

5.2) Ans;

$\frac{1}{R} = \frac{1}{R1} + \frac{1}{R2} \\ \frac{1}{R} = \frac{1}{8} + \frac{1}{10} \\ \frac{1}{R} = \frac{5 + 4}{40} = \frac{9}{40} \\ R = \frac{40}{9} = 4.4 \: \: ohm$

I hope I helped you^_^

7 0

2 years ago

Can you help me ASAPPP please help me

AveGali [126]

Answer:it is a

Explanation hope this helps .

6 0

3 years ago

How does light behave when a laser is pointed at a prism?

Gnoma [55]

Answer:

So when you shine a laser through a prism, there's nothing to be separated, and the light stays together.

Explanation:

7 0

2 years ago

A sailboat weighing 980 lb with its occupants is running downwind at 8 mi/h when its spinnaker is raised to increase its speed.

Effectus [21]

Answer:

78.498N

Explanation:

The Net force provided by the spinnaker can be obtained from Newton's second law of motion as follows;

$F=\frac{m(v-u)}{t}................(1)$

where m is the mass, v is the final velocity, u is the initial velocity and t is the time interval for which the force acted.

Given;

m =980lb

v = 12mi/h

u =8mi/hr

t = 10s.

It is important to convert all quantities to their SI units where necessary, so we do that as follows;

1lb = 0.45kg,

hence 980lb = 980 x 0.45kg = 441kg.

1mile = 1609.34m

1hour = 3600s,

therefore;

$8mi/h=\frac{8*1609.34m}{3600s}=3.58m/s$

$12mi/h=\frac{12*1609.34m}{3600s}=5.36m/s$

Substituting all values into equation (1), we obtain the following;

$F=\frac{441(5.36-3.58)}{10}\\F=\frac{441*1.78}{10}\\F=\frac{784.98}{10}\\F=78.498N$

4 0

3 years ago

A 320-kg satellite experiences a gravitational force of 800 N. What is the radius of the satellite’s orbit? What is its altitude

Westkost [7]

Answer:

Radius of orbit = 3.992 × $10^{7}$ m

Altitude of Satellite =33541.9× m

Explanation:

Formula for gravitational force for a satellite of mass m moving in an orbit of radius r around a planet of mass M is given by;

$F= G\frac{m M}{r^{2} }$

Where G = Gravitational constant = 6.67408 × 10-11 $\frac{m^{3} }{Kg sec^{2} }$

We are given

F= 800 N

m = 320 Kg

M = 5.972 × $10^{24}$ Kg

G = 6.67408 × 10-11 $\frac{m^{3} }{Kg sec^{2} }$

We have to find radius r =?

putting values in formula;

==> 800 =6.67408 × $10^{-11}$ × 320 × 5.972 × $10^{24}$ / $r^{2}$

==> 800= 39.8576 × $10^{13}$ × 320 / $r^{2}$

==> 800 = 12754.43 × $10^{13}$ / $r^{2}$

==> $r^{2}$ = 12754.43 × $10^{13}$ /800

==> $r^{2}$ =15.94 × $10^{13}$

==> r = 3.992 × $10^{7}$ m

==> r = 39920× $10^{3}$ m

This is the distance of satellite from center of earth. To find altitude we need distance from surface of earth. So we will subtract radius of earth from this number to find altitude.

Radius of earth =6378.1 km = 6378.1 × $10^{3}$ m

Altitude = 39920× $10^{3}$ - 6378.1 ×

3 0

3 years ago