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Zanzabum
3 years ago
6

A stock solution of Blue #1 has a concentration of 5.736 M. 3 mL of this solution is diluted with 8 mL water. What is the concen

tration of the resulting solution? Provide your response to 3 significant figures.
Chemistry
1 answer:
8_murik_8 [283]3 years ago
6 0

Answer:

1.56 M

Explanation:

This is a dilution process and so a dilution formula is suitably used as follows C1V1 = C2V2 where

C1 = concentration of the stock solution

V1 = volume of the stock solution

C2 = concentration of the resulting (dilute) solution and

V2 = the volume of the resulting (dilute) solution

C1V1 = C2V2 (Making C2 subject of the formula)

C2 = C1V1/V2

Given: C1 = 5.736 M; V1 = 3 Ml; V2 = (3+8) 11 Ml

C2 = 5.736 x 3 / 11

C2 = 1.56 M

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3 years ago
Calculate the concentration of A bottle of wine contains 12.9% ethanol by volume. The density of ethanol (CH3OH) is 0.789 g/cm e
Delicious77 [7]

Answer:

The mass percentage of the solution is 10.46%.

The molality of the solution is 2.5403 mol/kg.

Explanation:

A bottle of wine contains 12.9% ethanol by volume.

This means that in 100 mL of solution 12.9  L of alcohol is present.

Volume of alcohol = v = 12.9 L

Mass of the ethanol = m

Density of the ethanol ,d= 0.789 g/cm^3=0.789 g/mL

1 cm^3=1 mL

m=d\times v=0.798 g/ml\times 12.9 mL = 10.1781 g

Mass of water = M

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Density of water = D=1.00 g/mL

M=D\times V=1.00 g/ml\times 87.1 mL =87.1 g

Mass percent

(w/w)\%=\frac{m}{m+M}\times 100

\frac{10.1781 g}{10.1781 g+87.1 g}\times 100=10.46\%

Molality :

m=\frac{m}{\text{molar mass of ethanol}\times M(kg)}

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3 years ago
Question 10(Multiple Choice Worth 5 points)
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Answer:

O Generation of electricity

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Therefore the correct answer is <u>c</u>, electronegativity tends to increases across a period.

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