3 years ago

Need help with the 1st one

1 answer:

7 0

If I’m right this should be the answer

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pishuonlain [190]

Answer:

CH2 will be CH-CH2-CH2OH

CH3-CH will beCH-CH2OH

CH2 will be C(CH3)-CH2OH

3 0

3 years ago

Leno4ka [110]

The answer is letter a. Hill terrain, hill slope, and hill elevation

6 0

3 years ago

OLga [1]

Answer:

weil es in der Luft schwebt

5 0

2 years ago

Andrew [12]

1 and 5 are definitely significant. The zeros might not be significant .

8 0

3 years ago

snow_tiger [21]

Answer: Option (d) is the correct answer.

Explanation:

It is given that molecular formula is $C_{9}H_{16}$ . Now, we will calculate the degree of unsaturation as follows.

Degree of unsaturation = $C_{n} - \frac{\text{monovalent}}{2} + \frac{\text{trivalent}}{2} + 1$

= $9 - \frac{16}{2} + 1$

= 9 - 8 + 1

= 2

As the degree of unsaturation comes out to be 2. It means that this compound will contain one ring and one double bond.

Yes, this compound could be an alkyne as for alkyne D.B.E = 2.

But this compound cannot be a cycloalkane because for a cycloalkane D.B.E = 1 which is due to the ring only.

Thus, we can conclude that it is a cycloalkane is not a structural possibility for this hydrocarbon.

6 0

4 years ago