Question

For Mn3+, write an equation that shows how the cation acts as an acid.

Answer 1

An acid is a compound which will give H+ ions or H3O^+  ions

the reaction will be

$[Mn(H_{2}O )_{6} ^{+3} +H_{2}O --> [MnOH(H_{2}O)_{5}]^{+2} + H_{3}O^{+}$

Thus as there is evolution of H_{3}O^{+} the Mn+3 is an acid

Answer 2

The equation that shows ${\text{M}}{{\text{n}}^{3 + }}$  acts as the acid is

$\boxed{{{\left[{{\text{Mn}}{{\left({{{\text{H}}_2}{\text{O}}}\right)}_6}}\right]}^{3 + }}+{{\text{H}}_2}{\text{O}}\to{{\left[ {{\text{MnOH}}{{\left({{{\text{H}}_2}{\text{O}}} \right)}_5}}\right]}^{2 + }}{{\text{H}}_3}{{\text{O}}^ + }}$

Further Explanation:

Acids and bases can be defined in many ways based on different theories, which are as follows:

1. Arrhenius theory: According to this theory, acid is defined as the one which produces hydrogen or hydronium ions in a solution, while the base is defined as the one which produces hydroxide ions in a solution. Examples of Arrhenius acids include HBr, ${\text{HN}}{{\text{O}}_3}$ and  ${{\text{H}}_2}{\text{S}}{{\text{O}}_4}$ while NaOH and KOH are examples of Arrhenius bases.

2. Bronsted-Lowry theory: According to this theory, the acid in the reaction donates a proton while a base is one that accepts a proton. HCl acts as Bronsted acid while ${\text{N}}{{\text{H}}_3}$ is a Bronsted base.

3. Lewis theory: According to this theory, an acid accepts a pair of electrons to electron-rich species while a base donates electrons to electron-deficient species in the reaction. Examples of Lewis acids are ${\text{B}}{{\text{F}}_3}$ , ${\text{S}}{{\text{O}}_3}$ while ${{\text{H}}_2}{\text{O}}$ and ROH are the examples of Lewis base.

The equation to show the acidic nature of ${\mathbf{M}}{{\mathbf{n}}^{{\mathbf{3 + }}}}$ is as follows:

${\left[ {{\text{Mn}}{{\left({{{\text{H}}_2}{\text{O}}}\right)}_6}}\right]^{3 + }}+{{\text{H}}_2}{\text{O}}\to {\left[{{\text{MnOH}}{{\left( {{{\text{H}}_2}{\text{O}}}\right)}_5}} \right]^{2+}}+{{\text{H}}_3}{{\text{O}}^+}$

Here, ${\text{M}}{{\text{n}}^{3 + }}$ exists as ${\left[{{\text{Mn}}{{\left( {{{\text{H}}_2}{\text{O}}}\right)}_6}}\right]^{3 + }}$ in the aqueous medium. It reacts with water molecule to form ${\left[{{\mathbf{MnOH}}{{\left( {{{\mathbf{H}}_{\mathbf{2}}}{\mathbf{O}}} \right)}_{\mathbf{5}}}} \right]^{{\mathbf{2 + }}}}$ and ${{\mathbf{H}}_{\mathbf{3}}}{{\mathbf{O}}^{\mathbf{ + }}}$ is also released during the reaction.

Learn more:

1. The reason for the acidity of water brainly.com/question/1550328

2. Reason for the acidic and basic nature of amino acid brainly.com/question/5050077

Answer details:

Grade: High School

Subject: Chemistry

Chapter: Chemical reaction and equation

Keywords: acid, Mn3+, Arrhenius theory, Bronsted-Lowry theory, Lewis theory, H3O+, HCl, NH3, BF3, SO3, hydrogen ions, hydronium ions, hydroxide ions, aqueous, water, Mn(H20)63+, MnOH(H2O)63+, H2O, accepts, donates, electrons, reaction, proton.