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-Dominant- [34]
3 years ago
7

For Mn3+, write an equation that shows how the cation acts as an acid.

Chemistry
2 answers:
Mkey [24]3 years ago
8 0

An acid is a compound which will give H+ ions or H3O^+  ions

the reaction will be

[Mn(H_{2}O )_{6} ^{+3} +H_{2}O --> [MnOH(H_{2}O)_{5}]^{+2} + H_{3}O^{+}

Thus as there is evolution of H_{3}O^{+} the Mn+3 is an acid

yuradex [85]3 years ago
7 0

The equation that shows {\text{M}}{{\text{n}}^{3 + }}  acts as the acid is

\boxed{{{\left[{{\text{Mn}}{{\left({{{\text{H}}_2}{\text{O}}}\right)}_6}}\right]}^{3 + }}+{{\text{H}}_2}{\text{O}}\to{{\left[ {{\text{MnOH}}{{\left({{{\text{H}}_2}{\text{O}}} \right)}_5}}\right]}^{2 + }}{{\text{H}}_3}{{\text{O}}^ + }}

Further Explanation:

Acids and bases can be defined in many ways based on different theories, which are as follows:

1. Arrhenius theory: According to this theory, acid is defined as the one which produces hydrogen or hydronium ions in a solution, while the base is defined as the one which produces hydroxide ions in a solution. Examples of Arrhenius acids include HBr, {\text{HN}}{{\text{O}}_3} and  {{\text{H}}_2}{\text{S}}{{\text{O}}_4} while NaOH and KOH are examples of Arrhenius bases.

2. Bronsted-Lowry theory: According to this theory, the acid in the reaction donates a proton while a base is one that accepts a proton. HCl acts as Bronsted acid while {\text{N}}{{\text{H}}_3} is a Bronsted base.

3. Lewis theory: According to this theory, an acid accepts a pair of electrons to electron-rich species while a base donates electrons to electron-deficient species in the reaction. Examples of Lewis acids are {\text{B}}{{\text{F}}_3} , {\text{S}}{{\text{O}}_3} while {{\text{H}}_2}{\text{O}} and ROH are the examples of Lewis base.

The equation to show the acidic nature of {\mathbf{M}}{{\mathbf{n}}^{{\mathbf{3 + }}}} is as follows:

{\left[ {{\text{Mn}}{{\left({{{\text{H}}_2}{\text{O}}}\right)}_6}}\right]^{3 + }}+{{\text{H}}_2}{\text{O}}\to {\left[{{\text{MnOH}}{{\left( {{{\text{H}}_2}{\text{O}}}\right)}_5}} \right]^{2+}}+{{\text{H}}_3}{{\text{O}}^+}

Here, {\text{M}}{{\text{n}}^{3 + }} exists as {\left[{{\text{Mn}}{{\left( {{{\text{H}}_2}{\text{O}}}\right)}_6}}\right]^{3 + }} in the aqueous medium. It reacts with water molecule to form {\left[{{\mathbf{MnOH}}{{\left( {{{\mathbf{H}}_{\mathbf{2}}}{\mathbf{O}}} \right)}_{\mathbf{5}}}} \right]^{{\mathbf{2 + }}}} and {{\mathbf{H}}_{\mathbf{3}}}{{\mathbf{O}}^{\mathbf{ + }}} is also released during the reaction.

Learn more:

1. The reason for the acidity of water brainly.com/question/1550328

2. Reason for the acidic and basic nature of amino acid brainly.com/question/5050077

Answer details:

Grade: High School

Subject: Chemistry

Chapter: Chemical reaction and equation

Keywords: acid, Mn3+, Arrhenius theory, Bronsted-Lowry theory, Lewis theory, H3O+, HCl, NH3, BF3, SO3, hydrogen ions, hydronium ions, hydroxide ions, aqueous, water, Mn(H20)63+, MnOH(H2O)63+, H2O, accepts, donates, electrons, reaction, proton.

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A sample of bleach was analyzed as in this procedure. The only procedural difference is that the student weighed out the bleach
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Answer:

% = 5.69%

Explanation:

To do this, we need to write the equations taking place here. First, this is a REDOX reaction where the hypoclorite and thiosulfate solution reacts. The balanced equations are:

ClO⁻ + 2I⁻ + 2H⁺ -------> Cl⁻ +  I₂ + H₂O

I₂ + 2S₂O₃²⁻ -----------> 2I⁻ + S₄O₆²⁻

We already have the required volume and concentration of the thiosulfate solution, so we can calculate the moles of thiosulfate. With this moles, we can calculate the moles of hypochlorite, then the mass and finally the %.

The moles of thiosulfate would be:

moles S₂O₃²⁻ = V * M

moles S₂O₃²⁻ = 0.01324 * 0.0732 = 9.69x10⁻⁴ moles

Now according to the above reactions, we can see that

moles I₂ = moles ClO⁻

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moles I₂ / moles S₂O₃²⁻ = 1/2

Therefore, let's calculate the moles of ClO⁻:

moles ClO⁻ = 9.69x10⁻⁴ / 2 = 4.845x10⁻⁴ moles

Now, we can calculate the mass of these moles, using the molar mass of sodium hypochlorite which is 74.44 g/mol:

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