Answer:
34.8 moles of CO₂ are produced
Explanation:
This is the reaction:
1C₅H₁₂ + 8O₂ → 6H₂O + 5CO₂
Ratio is 1:5. We make a rule of three
1 mol of pentane can produce 5 moles of CO₂
Then, 6.96 moles of pentane may produce (6.96 .5) / 1 = 34.8 moles
Answer: Option (d) is the correct answer.
Explanation:
Steps involved for the given reaction will be as follows.
Step 1:
(fast)
Rate expression for step 1 is as follows.
Rate = k ![[NO]^{2}](https://tex.z-dn.net/?f=%5BNO%5D%5E%7B2%7D)
Step 2: ![N_{2}O_{2} + H_{2} \rightarrow N_{2}O + H_{2}O](https://tex.z-dn.net/?f=N_%7B2%7DO_%7B2%7D%20%2B%20H_%7B2%7D%20%5Crightarrow%20N_%7B2%7DO%20%2B%20H_%7B2%7DO)
This step 2 is a slow step. Hence, it is a rate determining step.
Step 3.
(fast)
Here,
is intermediate in nature.
All the steps are bimolecular and it is a second order reaction. Also, there is no catalyst present in this reaction.
Thus, we can conclude that the statement step 1 is the rate determining step, concerning this mechanism is not directly supported by the information provided.
Answer:
3 moles of O2 needed
Explanation:
2 moles of Mg to one mole O2
so 3 moles of O2 needed