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2 years ago

What biological molecules provide energy and structural support to living organisms?

Chemistry

1 answer:

Romashka [77]2 years ago

3 0

Answer:

Option D: Carbohydrates

Explanation:

Carbohydrates are a group of macromolecules that are a vital energy source for the cell, provide structural support to many organisms, and can be found on the surface of the cell as receptors or for cell recognition.

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No explanation needed, just a quick answer please!

tresset_1 [31]

all of the above is the answer :)

8 0

3 years ago

What pressure will be exerted by 25 g of CO2 at temperature of 25°C and a volume of .50 L?

Grace [21]

Answer:

P = 27.9 atm

Explanation:

Given data:

Mass of CO₂ = 25 g

Temperature = 25°C (25+273.15 K = 298.15 K)

Volume of gas = 0.50 L

Pressure of gas = ?

Solution:

Firs of all we will calculate the number of moles of gas,

Number of moles = mass/molar mass

Number of moles = 25 g/ 44 g/mol

Number of moles = 0.57 mol

Pressure of gas :

PV = nRT

P= Pressure

V = volume

n = number of moles

R = general gas constant = 0.0821 atm.L/ mol.K

T = temperature in kelvin

P × 0.50 L = 0.57 mol × 0.0821 atm.L/ mol.K × 298.15 K

P = 13.95 atm.L/ 0.50 L

P = 27.9 atm

4 0

2 years ago

I don’t understand the equations

inna [77]

So the equation is balanced, meaning they have the smallest amounts of each element in the reactants to create the products.

So, 2 moles of H2S (the coefficient) contributes to 2 moles Ag2S, which is why the ratio is 2:2.

I hope that made sense.

6 0

2 years ago

What mass of copper sulphate dissolves in 100g of water at 70 °C

ValentinkaMS [17]

The answer mass of copper sulphate is

46g

6 0

2 years ago

A compound, C4H6O, exhibits IR absorption at 1705 cm-1. Its carbon NMR shifts are given below. The number of hydrogens at each c

Airida [17]

Answer:

Methacrylaldehyde

Explanation:

The first step is the calculation of the IHD (index hydrogen deficiency):

$IHD=~\frac{2C+2+N-H-X}{2}$

$IHD=~\frac{2(2)+2-6}{2}=2$

This value indicates that we have 2 double bonds. Now, if we check the IR info we can conclude that we have an oxo group (C=O) due to the signal in 1705 cm^-1 . So, the options that we can have are aldehyde or ketone.

If we analyze the NMR info we have a signal in 194.7 with only 1 hydrogen. This indicates that necessary we have an aldehyde due to the hydrogen. Also, for the signal in 14 we will have a $CH_3$ , for the signal at 134.2 we will have a $CH_2$ and for the signal at 146.0 we will have a quaternary carbon (no hydrogens present).

So, we will have a $CH_3$ , $CH_2$ , C (without hydrogens), an aldehyde group and a double bond.

When we put all this together we will obtain the Methacrylaldehyde (see figure).

5 0

3 years ago