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user100 [1]
3 years ago
7

What biological molecules provide energy and structural support to living organisms?

Chemistry
1 answer:
Romashka [77]3 years ago
3 0

Answer:

Option D: Carbohydrates

Explanation:

Carbohydrates are a group of macromolecules that are a vital energy source for the cell, provide structural support to many organisms, and can be found on the surface of the cell as receptors or for cell recognition.

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2.<br> An alkane has at least on C=C<br> bond.<br> ut of<br> Select one:<br> O True<br> O False
garik1379 [7]
I think it’s false?????
8 0
3 years ago
The volume of carbon gas at 5.0 ATM was measured to be 363 ml. What will the pressure be if the volume is change to .00020 ml?
aleksley [76]

Answer:

The answer to your question is P2 = 9075000 atm

Explanation:

Data

Pressure 1 = P1 = 5 atm

Volume 1 = V1 = 363 ml

Pressure 2 = P2 = ?

Volume 2 = 0.0002 ml

Process

To solve this problem use Boyle's law

                 P1V1 = P2V2

-Solve for P2

                 P2 = P1V1/V2

-Substitution

                  P2 = (5 x 363) / 0.0002

-Simplification

                  P2 = 1815 / 0.0002

-Result

                 P2 = 9075000 atm

5 0
3 years ago
PLS help
viktelen [127]

Answer:

d . Sc2O5

Explanation:

Hello,

In this case, when forming oxides from a metal and oxygen, for us to find out each element's subscript, we must exchange them as shown below, considering +5 for scandium:

Sc^{+5}_2O^{-2}_5

For that reason, the answer is d . Sc2O5

Best regards.

3 0
3 years ago
Read 2 more answers
Calculate (a) the pH of a 0.0250 M solution of phenylacetic acid, and (b) the pH of a 0.0500 M solution of sodium phenylacetate.
almond37 [142]

Answer:

Explanation:cool thre answer is 009000000000.1 because you have to add them so ye

6 0
3 years ago
The burning of a sample of propane
r-ruslan [8.4K]

Answer:

70.0°C

Explanation:

We are given;

  • Amount of heat generated by propane as 104.6 kJ or 104600 Joules
  • Mass of water is 500 g
  • Initial temperature as 20.0 ° C

We are required to determine the final temperature of water;

Taking the initial temperature is x°C

We know that the specific heat of water is 4.18 J/g°C

Quantity of heat = Mass × specific heat × change in temperature

In this case;

Change in temp =(x-20)° C

Therefore;

104600 J = 500 g × 4.18 J/g°C × (x-20)

104600 J = 2090x -41800

146400 = 2090 x

  x = 70.0479

     =70.0 °C

Thus, the final temperature of water is 70.0°C

7 0
3 years ago
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