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user100 [1]
3 years ago
7

What biological molecules provide energy and structural support to living organisms?

Chemistry
1 answer:
Romashka [77]3 years ago
3 0

Answer:

Option D: Carbohydrates

Explanation:

Carbohydrates are a group of macromolecules that are a vital energy source for the cell, provide structural support to many organisms, and can be found on the surface of the cell as receptors or for cell recognition.

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What is one differrence between a mixture and a compound
Ann [662]

Answer:

A mixture can contain components in any proportions while a compound contains components in fixed proportions. All components in a mixture do not chemically react, while the components in a compound do react and their original properties are lost.

3 0
3 years ago
Balance the following chemical reactions:
Tcecarenko [31]

1. 2Pb(NO₃)₂ → 2PbO + 4NO₂ + O₂

2. CH₄ + 2O₂ → CO₂ + 2H₂O

3. Cu + 2AgNO₃ → Cu(NO₃)₂ + 2Ag

4. MnO₂ + 4HCl → MnCl₂ + 2H₂O + Cl₂

5. Pb(NO₃)₂ + 2NaCl → PbCl₂ + 2NaNO₃

1)

NaCl+AgNO_3=>NaNO_3+AgC\downarrow

2)

CuSO_4+Cu_2Cl_2\neq>

CuSO_4+Cu_2l_2\neq

4 0
3 years ago
Read 2 more answers
How many liters of 15.0 molar NaOH stock solution will be needed to make 17.5 liters of a 1.4 molar NaOH solution? Show the work
strojnjashka [21]
2.0 L
The key to any dilution calculation is the dilution factor

The dilution factor essentially tells you how concentrated the stock solution was compared with the diluted solution.

In your case, the dilution must take you from a concentrated hydrochloric acid solution of 18.5 M to a diluted solution of 1.5 M, so the dilution factor must be equal to

DF=18.5M1.5M=12.333

So, in order to decrease the concentration of the stock solution by a factor of 12.333, you must increase its volume by a factor of 12.333by adding water.

The volume of the stock solution needed for this dilution will be

DF=VdilutedVstock⇒Vstock=VdilutedDF

Plug in your values to find

Vstock=25.0 L12.333=2.0 L−−−−−

The answer is rounded to two sig figs, the number of significant figures you have for the concentration od the diluted solution.

So, to make 25.0 L of 1.5 M hydrochloric acid solution, take 2.0 L of 18.5 M hydrochloric acid solution and dilute it to a final volume of 25.0 L.

IMPORTANT NOTE! Do not forget that you must always add concentrated acid to water and not the other way around!

In this case, you're working with very concentrated hydrochloric acid, so it would be best to keep the stock solution and the water needed for the dilution in an ice bath before the dilution.

Also, it would be best to perform the dilution in several steps using smaller doses of stock solution. Don't forget to stir as you're adding the acid!

So, to dilute your solution, take several steps to add the concentrated acid solution to enough water to ensure that the final is as close to 25.0 L as possible. If you're still a couple of milliliters short of the target volume, finish the dilution by adding water.

Always remember

Water to concentrated acid →.NO!

Concentrated acid to water →.YES!
8 0
3 years ago
Ethyl acetate reacts with H2, in the presence of a catalyst to yield ethyl alcohol: C4H8O2 + 2H2--> 2C2H6O. A. How many grams
Anni [7]
The balanced chemical reaction is:

<span>C4H8O2 + 2H2--> 2C2H6O

</span>A. How many grams of ethyl alcohol are produced by reaction of 2.7 mol of ethyl acetate with H2? 2.7 mol C4H8O2 ( 2 mol C2H6O / 1 mol C4H8O2) (46.07 g / 1 mol) = 248.78 g ethyl alcohol

B. How many grams of ethyl alcohol are produced by reaction of 13.0g of ethyl acetate with H2?
13.0 g C4H8O2 ( 1 mol / 88.11 g) ( 2 mol C2H6O / 1 mol C4H8O2) (<span>46.07 g / 1 mol) = 13.59 g ethyl alcohol</span>

C. How many grams of H2 are needed to react with 13.0g of ethyl acetate?
13.0 g C4H8O2 ( 1 mol / 88.11 g) ( 2 mol H2 / 1 mol C4H8O2) (2.02 g / 1 mol) = 0.5961 g H2
6 0
3 years ago
Inferring conclusions if you find an element in nature in its pure elemental state what can you infer about the elements chemica
Grace [21]

Answer;

-Not that reactive

The element found is not very reactive.

Explanation;

-If an element is found in nature in its pure elemental state then the the element found is not very reactive.

-There are many elements which are not much reactive. such as in metals- Ag, Au, Hg, Cu etc. and in Non metals- O2, N2, Inert gases etc.

- For checking its chemical properties you will have to examine it with O2 or C-12.


3 0
2 years ago
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