The balanced equation
for the reaction is
CO(g) + 2H₂(g) ⇄ CH₃OH(g)
The given
concentrations are at equilibrium state. Hence we can use them directly in
calculation with the expression for the equilibrium constant, k.
expression for k can be written as
k = [CH₃OH(g)] / [CO(g)] [H₂<span>(g) ]²
</span>[H₂<span>]=0.072 M
[CO]= 0.020M
[CH</span>₃OH]= 0.030 M
From substitution,
k = 0.030
M / 0.020 M x (0.072 M)²
k =
289.35 M⁻²
<span>
Hence, equilibrium constant for the given reaction at 700 K is 289.35 M</span>⁻².
<span> </span>
Answer:
BrF3 has 2 lone pairs (4 unshared electrons)
Explanation:
Answer:
Phosphorous.
Explanation:
In 1649 Hennig Brand discovered phosphorous.
Answer: letter b.
Why?
Because Entropy(ΔS) INCREASES when INCREASING disorder in a reaction.
A. INCORRECT. Negative ΔS. This is because there are less molecules of gas in the products compared to the reactants.
B. CORRECT. Positive ΔS. This is because you are increasing disorder by breaking down a solid(highly ordered) molecule into two ions in solution(in solution they are less ordered).
C. INCORRECT. Negative ΔS. This is because you are going from a (g)gas which has more disorder to a (s)solid which has much less disorder than a gas.
D. INCORRECT. Negative ΔS. This is because you are decreasing disorder by building a single molecule. There are also more moles of gas on the reactants side indicating a negative ΔS.
Please comment with any further questions. Hope this helped!
Answer:
if im right i do my caculation that it is B
