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Montano1993 [528]
3 years ago
5

A bag is dropped from a hovering helicopter. When the bag has fallen 2 seconds,

Physics
1 answer:
denis-greek [22]3 years ago
5 0
A) Vt = Vo - gt
= 0 - 9.8 . 2
= - 19.6 m/sec (acting downward)
b) ∆y = Vt^2 - Vo^2 / 2g
= (-19.6)^2 - 0 / 19.6 = 19.6 meters
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Explanation:

<h3>mark as brainliast</h3>

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