A surface wave is a wave that travels along the surface of a medium. The medium is the matter through which the wave travels. Ocean waves are the best-known examples of surface waves. They travel on the surface of the water between the ocean and the air. (According to ck12.org) 
So your answer would be A!
        
                    
             
        
        
        
The work that is required to increase the speed to 16 knots is 14,176.47 Joules
If a catamaran with a mass of 5.44×10^3 kg is moving at 12 knots, hence;
5.44×10^3 kg = 12 knots
For an increased speed to 16knots, we will have:
x = 16knots
Divide both expressions

To get the required work done, we will divide the mass by the speed of one knot to have:

Hence the work that is required to increase the speed to 16 knots is 14,176.47 Joules
Learn more here: brainly.com/question/25573786
 
        
             
        
        
        
Any ride that oscillates back and forth or moves only in a complete circle utilizes periodic motion.
        
             
        
        
        
The current intensity is defined as the amount of charge flowing through a certain point of a wire divided by the time interval:

where Q is the charge and 

 is the time. Re-arranging the formula, we have

for the compressor in our problem, the intensity of current is I=66.1 A, while the time is 

, so the amount of charge that crosses a certain point of the circuit during this time is
 
 
        
        
        
Answer:
0.48 m
Explanation:
I'm assuming that this takes place in an ideal situation, where we neglect a host of factors such as friction, weight of the spring and others 
If the mass is hanging from equilibrium at 0.42 m above the floor, from the question, and it is then pulled 0.06 m below that particular position. This pulling is a means of adding more energy into the spring, when it is released, the weight compresses the spring and equals its distance (i.e, 0.06 m) above the height.
0.42 m + 0.06 m = 0.48 m 
At the highest point thus, the height is 0.48 m above the ground.