A person pushes horizontally on a heavy box and slides it across the level floor at constant velocity. The person pushes with a
60.0 N force for the first 7.09 m, at which time he begins to tire. The force he exerts then starts to decrease linearly from 60.0 N to 0.00 N across the remaining 7.09 m. How much total work did the person do on the box?
1 answer:
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Explanation :
There are two types of collision i.e. elastic and elastic collision.
- Elastic collision : In this type of collision, the total momentum and the kinetic energy of the particles remains constant.
- Inelastic collision : In this type of collision, only the momentum remains constant while there is some loss of kinetic energy occurs.
From Newton's second law,
F = m a
a is the rate of change of velocity.
There is a inverse relation between the force and the time of collision.
The change in <em><u>momentum</u></em> will remain the same during a collision, the force needed to bring an object to a stop can be <em><u>increased</u></em> if the time of the collision is <u><em>decreased</em></u>.
Answer:
Explanation:
It is given that,
Mass of the baseball, m = 0.14 kg
It is dropped form a height of 1.8 m above the ground. Let u is the velocity when it hits the ground. Using the conservation of energy as :
h = 1.8 m
u = 5.93 m/s
Let v is the speed of the ball when it rebounds. Again using the conservation of energy to find it :
h' = 1.4 m
v = -5.23 m/s
The change in the momentum of the ball is given by :
So, the change in the ball's momentum occurs when the ball hits the ground is 1.56 kg-m/s. Hence, this is the required solution.