All categories

3 years ago

Question is in the picture. Please help

Mathematics

1 answer:

loris [4]3 years ago

7 0

One pair of adjacent sides are congruent (WZ and ZY) so as WXYZ is a parallelogram all sides are congruent.

You might be interested in

Which of the points are solutions to the inequality check all that apply identifying solutions to any quality

swat32

Answer:

(0, -4)

Step-by-step explanation:

4 0

3 years ago

What are the intercepts for the equation? Select all that apply. x + y = 4 *

olchik [2.2K]

Answer:

y intercept (0, 4)

x intercept (4, 0)

I hope this is good enough:

3 0

3 years ago

Find the volume of this figure. round your answer to the nearest hundredth. if necessary #8

ivann1987 [24]

Answer:

30 miles²

Step-by-step explanation:

To solve the area of the prism we have to multiply the area of the base * the height of the prism. The base of the prism is a right triangle.

(b*h)÷2 = Area of a triangle

Base = 4

Height = 3

Now:

(4*3)/2 = 6 miles²

Now we have to multiply 6 miles² by 5 as our height.

We get 30 miles² as the volume of the figure.

4 0

2 years ago

David is playing a trivia game where he gains points for correct answers and loses points for incorrect answers. At the start of

lord [1]

At the end of Round 3, David's score would be 2000.

6 0

3 years ago

Water is leaking out of an inverted conical tank at a rate of 6800.0 cubic centimeters per min at the same time that water is be

m_a_m_a [10]

Answer:

6.82 $mt^3/min$

Step-by-step explanation:

By congruence of triangles, the radius r of the cone base when its height is 1 meter satisfies the relation

r/1 = 2.5/6

(See picture attached)

So, r = 0.4166 meters when the water is 1 meter high.

The volume of a cone with radius of the base = R is given by

$V=\frac{\pi R^2h}{3}$

So, the volume of water when it is 1 meter high is

$V=\frac{\pi* 0.(4166)^2}{3}=0.1817\;mt^3$

One minute later, the height of the water is 1 meter + 30 centimeters = 1.30 mt

The radius now satisfies

r/1.3 = 2.5/6

and now the radius of the base is

r = 0.5416 mt

and the new volume of water is $0.3071\;mt^3$

So, the water is raising at a speed of

0.3071-0.1871 = 0.12 $mt^3/min$

This speed equals the difference between the water being pumped and the water leaking,

So,

0.12 = Speed of water being pumped -6.8

and

Speed of water being pumped = 6.8+0.12 = 6.82 $mt^3/min$

8 0

3 years ago