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Allisa [31]
3 years ago
5

The weights of newborn baby boys born at a local hospital are believed to have a normal distribution with an average weight of 5

lbs and a standard deviation of 2 lb. If a newborn baby boy, born at the local hospital, is randomly selected, find the probability that the weight of the newborn baby boy will be between 5 lbs and 11 lbs.
Mathematics
1 answer:
Lisa [10]3 years ago
5 0

Answer: 0.4987

Step-by-step explanation:

Given : The weights of newborn baby boys born at a local hospital are believed to have a normal distribution with

Mean : \mu=5\text { lbs}

Standard deviation : \sigma= 2\text{ lbs}

Let X be the random variable that represents the weight of randomly selected student .

Z score : z=\dfrac{x-\mu}{\sigma}

For x = 5 lbs

z=\dfrac{5-5}{2}=0

For x = 11 lbs

z=\dfrac{11-5}{2}=3

By using the standard normal distribution table ,  the probability that the weight of the newborn baby boy will be between 5 lbs and 11 lbs :-

P(5

Hence, the probability that the weight of the newborn baby boy will be between 5 lbs and 11 lbs =0.4987

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I only need the equations, I can solve it.
natali 33 [55]
How can you solve it if you don't know the equations?  :P  Just kidding...

n+d=22, so we can say that d=22-n

5n+10d=120, and using d found above in this equation gives you:

5n+10(22-n)=120

5n+220-10n=120

-5n=-100

n=20, and since  d=22-n, d=2

So there are two dimes and twenty nickels...

check...

20(5)+2(10)=100+20=120 cents which is $1.20

n+d=22, 20+2=22, 22=22
4 0
3 years ago
Read 2 more answers
What is the midpoint of the coordinate F( -2, 4) and G(6, 1)
Marrrta [24]

Answer:

\huge\boxed{\left(2; 2\dfrac{1}{2}\right)}

Step-by-step explanation:

\text{The formula of a midpoint:}\\\\M\left(\dfrac{x_1+x_2}{2};\ \dfrac{y_1+y_2}{2}\right)\\\\\text{We have the points}\ F(-2,\ 4),\ G(6,\ 1).\\\\\text{Substitute:}\\\\M_{FG}\left(\dfrac{-2+6}{2};\ \dfrac{4+1}{2}\right)\to M_{FG}\left(\dfrac{4}{2};\ \dfrac{5}{2}\right)\to M_{FG}\left(2; 2\dfrac{1}{2}\right)

6 0
3 years ago
I need some help with this. If you could help me, that would be great.
Vesnalui [34]

Answer:

 .31 g / mL

Step-by-step explanation:

Density = mass / volume

Sample 3

mass = 7 1/4 = 7.25

Volume 23.1

Density = 7.25/ 23.1 = .313852814

To the nearest hundredth

  .31 g / mL

8 0
3 years ago
A woman bought some large frames for $10 each and some small frames for $5 each add a closeout sale if she bought 20 frames for
vampirchik [111]

Answer:

The quantity of large frames is 7

The quantity of small frames is 13

Step-by-step explanation:

Given as :

The price of each large frames = $ 10

The price of each small frames = $ 5

The total number of both frames bought = 20

The price for both the frames = $ 135

Now,

Let the quantity of large frames = L

And The quantity of small frames = S

So , According to question

The total number of both frames bought = 20

Or, The quantity of large frames + the quantity of small frame = 135

Or, L + S = 20         ......A

And $ 10 L + $ 5 S = $ 135                         ................B

Or, $ 10× ( L + S ) = $ 10× 20

Or, $ 10 L + $ 10 S = $ 200

(  $ 10 L + $ 10 S ) - ( $ 10 L + $ 5 S ) = $ 200 - $ 135

Or , ( $ 10 L - $ 10 L ) + ( $ 10 S - $ 5 S ) = $ 65

Or, 0 + 5 S = 65

∴  S = \frac{65}{5}

I.e S = 13

So, The quantity of small frames = S = 13

Put the Value of S in eq A

So , L + S = 20

Or, L = 20 - S

Or, L = 20 - 13

∴   L = 7

So, The quantity of large frames = L = 7

Hence The quantity of large frames is 7

And   The quantity of small frames is 13   Answer

7 0
3 years ago
6) A standard deck has 52 cards, and contains 13 cards of each of the four suits: diamonds, spades, hearts, and clubs. What is t
Crazy boy [7]

Answer:

\dfrac{12}{51}\cong\dfrac{4}{17}

Step-by-step explanation:

You have 52 cards in a deck and 13 cards of each suit.

The probability of picking a diamond in a complete deck of cards is:

\dfrac {13}{52}

Or the probability is 13 put of 52.

Since you took out 1 diamond card already there would be only 51 cards left and 12 diamond cards left. So you would have a probability of:

\dfrac{12}{51}

If we simplify it you will have a probability of:

\dfrac{4}{17}

6 0
3 years ago
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