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3 years ago

5x - 6х +2 4х2 - 3x Multiply

Mathematics

1 answer:

kipiarov [429]3 years ago

6 0

Answer:

x = 3

Step-by-step explanation:

So the equation is 5x - 6x + 2 = 4 x 2 - 3x

First we need to combine *like terms on both sides of the equal sign.

*like terms: there are three different types of numbers.

1) variable: a letter that represents an unknown number, usually the letters are x or y

2) coefficient: a number that is with a variable

3) constant: a number without a variable

You can't add or subtract or divide or multiply (in simple words, you cant combine) any numbers that aren't like terms.

And you also can't combine any numbers that are on the opposite side of the equal sign, even if they are like terms.

Back to the equation...

On the right side, the like terms are 5x and -6x.

On the left side, the like terms are 4 and 2.

After combining like terms, the equation is now simplified to

-x + 2 = 8 - 3x.

There are still other like terms that need to be combined, but they are on different sides of the equal sign.

But there is a way to move around the numbers!

By adding or subtracting, depending on whether the number is a positive or negative number.

Also you need to add/subtract them equally (meaning if you add/subtract a number from the left side, you also need to do the same on the right)

Back to the equation...

We first can add 3x to both sides.

Now, the equation is

-x + 2 + 3x = 8

Next, we can subtract 2 on both sides as well.

The equation is

-x + 3x = 8 - 2

Finally, we can combine the like terms.

Our equation is 2x = 6

The final step is to just get x by itself, without the coefficient.

To do this, we can divide 2 on both sides of the equal sign.

So the equation is x = 3, which is also our final answer.

Hope this helped :)

If it did, could you please give me brainliest?

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Solve the following using Substitution method 2x – 5y = -13 3x + 4y = 15

Digiron [165]

$\huge \boxed{\mathfrak{Question} \downarrow}$

Solve the following using Substitution method

2x – 5y = -13

3x + 4y = 15

$\large \boxed{\mathfrak{Answer \: with \: Explanation} \downarrow}$

$\left. \begin{array} { l } { 2 x - 5 y = - 13 } \\ { 3 x + 4 y = 15 } \end{array} \right.$

To solve a pair of equations using substitution, first solve one of the equations for one of the variables. Then substitute the result for that variable in the other equation.

$2x-5y=-13, \: 3x+4y=15$

Choose one of the equations and solve it for x by isolating x on the left-hand side of the equal sign. I'm choosing the 1st equation for now.

$2x-5y=-13$

Add 5y to both sides of the equation.

$2x=5y-13$

Divide both sides by 2.

$x=\frac{1}{2}\left(5y-13\right) \\$

Multiply $\frac{1}{2}\\$ times 5y - 13.

$x=\frac{5}{2}y-\frac{13}{2} \\$

Substitute $\frac{5y-13}{2}\\$ for x in the other equation, 3x + 4y = 15.

$3\left(\frac{5}{2}y-\frac{13}{2}\right)+4y=15 \\$

Multiply 3 times $\frac{5y-13}{2}\\$ .

$\frac{15}{2}y-\frac{39}{2}+4y=15 \\$

Add $\frac{15y}{2} \\$ to 4y.

$\frac{23}{2}y-\frac{39}{2}=15 \\$

Add $\frac{39}{2}\\$ to both sides of the equation.

$\frac{23}{2}y=\frac{69}{2} \\$

Divide both sides of the equation by 23/2, which is the same as multiplying both sides by the reciprocal of the fraction.

$\large \underline{ \underline{ \sf \: y=3 }}$

Substitute 3 for y in $x=\frac{5}{2}y-\frac{13}{2}\\$ . Because the resulting equation contains only one variable, you can solve for x directly.

$x=\frac{5}{2}\times 3-\frac{13}{2} \\$

Multiply 5/2 times 3.

$x=\frac{15-13}{2} \\$

Add $-\frac{13}{2}\\$ to $\frac{15}{2}\\$ by finding a common denominator and adding the numerators. Then reduce the fraction to its lowest terms if possible.