Answer:
The cornea of an eye is avascular
Explanation:
The healing process in case of a cornea transplant is slow, because the cornea is of an eye is avascular, i.e., it does not contain blood vessels and in the absence of the blood vessels in the cornea tissue the nutrients and oxygen is not able to get delivered there.
Thus the immune system, without the blood vessels in the cornea is weak and hence healing takes time in case of cornea transplant.
Answer:
100 mph
Explanation:
Average speed = distance / time
v = 250 mi / 2.5 hr
v = 100 mi/hr
Ah hah ! There's an easy way and a hard way to do this one.
If it's OK with you, I'm gonna do it the easy way, and not even
talk about the hard way !
First, let's look at a few things in this question.
-- "gravitational force between a planet and a mass"
This is just a complicated way to say "How much does the mass weigh ?"
That's what we have to find.
-- If we know the mass, how do we find the weight ?
Multiply the mass by the acceleration of gravity there.
Weight = (mass) x (gravity) .
-- Do we know the acceleration of gravity on this dark mysterious planet ?
We do if we read the second line of the question !
It's right there ... 8.8 m/s² .
-- We know the mass. We know gravity. And we know that
if you multiply them, you get the weight (forced of gravity).
I'm pretty sure that you can do the rest of the solution now.
weight = (mass) x (gravity)
Weight = (17 kg) x (8.8 m/s²)
Multiply them:
Weight = 149.6 kg-m/s²
That complicated-looking unit is the definition of a Newton !
So the weight is 149.6 Newtons. That's the answer. It's choice-A.
It's about 33.6 pounds.
When this mass is on the Earth, it weighs about 37.5 pounds.
But when it's on this planet, it only weighs about 33.6 pounds.
That's because gravity is less on this planet. (8.8 there, 9.8 on Earth)
Answer:
The momentum of block B = 27 Kg m/s
Explanation:
Given,
The initial momentum of block A, MU = 15 Kg m/s
The final momentum of block A, MV = -12 Kg m/s
Consider the block B is initially at rest.
Therefore, the initial momentum of block B, mu = 0
According to the laws of conservation of linear momentum, the momentum of the body before impact is equal to the momentum of the body after impact.
<em> MU + mu = MV + mv</em>
15 + (0) = (-12) + mv
mv = 15 + 12
= 27 Kg m/s
Hence, the momentum of the block B after impact is, mv = 27 Kg m/s
