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3 years ago

Present at least one example that illustrates acceleration. Is this a scalar or vector quantity? Explain why. ...?

Physics

2 answers:

Tatiana [17]3 years ago

8 0

Answer:

Vector

Explanation:

Acceleration is defined as the rate of change of velocity. As velocity is a vector quantity, so acceleration is also a vector quantity.

If a car starts from rest and attains some velocity after some time, then car is accelerating and the firection of acceleration is same as the direction of velocity.

If a car is moving and after applying the brakes it come to rest it means the motion of car has negative acceleration which means the direction of velocity and the direction of acceleration is opposite to each other.

SIZIF [17.4K]3 years ago

5 0

Acceleration is a vector because it has magnitude and direction

Example :
a Car stopping at the rate of 5 m/s. In this example, the direction of acceleration is the opposite of the direction of velocity, and the magnitude is 5 m/s

Hope this helps

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Law Incorporation [45]

My answer : the particle is quark

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3 years ago

Read 2 more answers

A machine pulls a 46 kg trunk 3.0 m up a 42o ramp at constant velocity, with the machine's force on the trunk directed parallel

Agata [3.3K]

Answer:

the answers are

W = 1271.256 J

$E_{th}$ = 361.81 J

Explanation:

The mass of the trunk (m) = 46kg

angle between the ramp and the horizontal (θ) = 42°

The trunk is pulled at a displacement (d) up the ramp = 3m

The coefficient of kinetic friction between the trunk and the ramp = 0.36

The trunk is moving with a constant velocity therefore the net force on it is zero, therefore the force required to move the trunk must be equal to the summation of forces opposing the trunk

The two forces opposing the trunk are

the gravitational force directed down the ramp $F_{g}$ and
the frictional force between the ramp and the trunk $F_{f}$

We have to calculate the machine's force which is equal to sum of the

$F =F_{g} + F_{f}$

$F_{g}$ = $mgsin$ θ

$F_{f} =$ μ× N

N = mgcosθ

$F_{f} =$ μ $mgcos$ θ

F = mg (sinθ + μcosθ)

F = 46× 9.8 (sin42 + 0.36×cos42)

F= 450.8 (0.67 +0.27)

F = 450.8 × 0.94

F = 423.752N

to calculate the workdone on the trunk by the machine force

The workdone on the trunk is = W = F × dcosΘ

Θ = 0° because the trunk is directed parallel to the ramp

W =423.752× 3 cos 0

W = 423.752 ×3

W = 1271.256 J

(b) the increase in thermal energy of the trunk and the ramp

Friction converts mechanical energy into thermal energy, so multiplying the frictional force with the distance gives the thermal energy generated by the trunk

$E_{th} =F_{f}$ × d

= μ $mgcos$ θ ×d

= 0.36 ×46×9.8×cos42×3

= 361.81 J

5 0

2 years ago

Read 2 more answers

A certain microwave has a

Tatiana [17]

Answer:

$9.375\times 10^{9} Hz$

Explanation:

Frequency is mathematically defined as the quotient of speed divided by wavelength.

$Frequency= \frac {v}{W}$

where

v-is the speed of light

-w is wavelength.

Given the speed of the wave as $V=300000000 \ m/s$ and the wavelength $\lambda= 0.032\ m$ , we substitute these values in the Frequency function to solve for frequency:

$Frequency=\frac {300000000}{0.032}=9375000000 Hz=9.375\times 10^{9} Hz$

Hence, the wave's frequency is $9.375\times 10^9\ Hz$

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3 years ago

How do lone pairs of electrons affect the bond angle differently than electrons shared in a bond?

lubasha [3.4K]

Answer:

Lone pairs cause bond angles to deviate away from the ideal bond angles

Explanation:

Bonded electrons are stabilized and clustered between the bonding electrons meaning they are much closer together. Non-bonding electrons however are not being shared between any atoms which allows them to roam a little further spreading the charge density over a larger space and therefore interfering with what would be an expected bond angle

3 0

2 years ago

A student walks 50 meters east, 40 meters north, 35 meters east, and then 20 m south. What is the magnitude and direction of the

Nuetrik [128]

Answer: A student walks 50 meters east, 40 meters north, 35 meters east, and then 20 m south. Then the magnitude and direction of the student's total displacement will be 87.32 m along the direction of AD or in east-south direction.

Explanation: To find the correct answer, we need to know about the Displacement of a body in motion.

<h3>What is displacement of a body in motion?</h3>

The displacement is the shortest distance between initial and final positions of a body.
It's a vector quantity, and can positive, negative, or zero.
The magnitude of displacement is less than or equal to the distance travelled.

<h3>How to solve the problem?</h3>

At first, we can draw a diagram showing the motion of the body.
From the diagram, the displacement of the body will be equal to the distance between point A and D.
To solve this, we can use Pythagoras theorem.

$AD=AC+CD\\AC^{2} =50^{2} +11^2\\AC=51.19 m\\Similarly,\\CD^2=35^2+9^2\\CD=36.13 m\\thus, \\AD=51.19+36.13=87.32 m$

Thus, from the above calculations, we can conclude that, the displacement of the body will be equal to 87.32 m along the direction of AD or in east-south direction.

Learn more about the Displacement here:

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3 0

2 years ago