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erica [24]
3 years ago
15

a boat costs $16600 and decreased in value by 14% per year. How much will the boat be worth after 11 years?

Mathematics
1 answer:
mr_godi [17]3 years ago
4 0

The worth of boat after 11 years is $ 3159.3013

<em><u>Solution:</u></em>

Given that,

Boat costs $16600 and decreased in value by 14% per year

To find: Worth of boat after 11 years

<em><u>The formula for decreasing function is given as:</u></em>

y = a(1-r)^t

Where,

y is the value after "t" years

t is the number of years

a is the initial value

r is decreasing rate in decimal

<em><u>From given,</u></em>

a = 16600

t = 11

r = 14 \% = \frac{14}{100} = 0.14

<em><u>Substituting the values we get,</u></em>

y = 16600(1-0.14)^{11}\\\\y = 16600(0.86)^{11}\\\\y = 16600 \times 0.1903\\\\y = 3159.3013

Thus the worth of boat after 11 years is $ 3159.3013

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Data given and notation    

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\alpha=0.05 represent the significance level for the hypothesis test.    

z would represent the statistic (variable of interest)    

p_v represent the p value for the test (variable of interest)    

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Alternative hypothesis:\mu \neq 1    

Since we know the population deviation, is better apply a z test to compare the actual mean to the reference value, and the statistic is given by:    

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Calculate the statistic    

We can replace in formula (1) the info given like this:    

z=\frac{1.02-1}{\frac{0.04}{\sqrt{40}}}=3.162    

P-value    

Since is a two-sided test the p value would be:    

p_v =2*P(z>3.162)=0.0016    

Conclusion    

If we compare the p value and the significance level given \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to to reject the null hypothesis, so we can conclude that the true mean is different from 1 pound at 5% of signficance.    

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