Answer:
Explanation:
Time period of satellite T = 6.43 X 60 X 60 s
acceleration = ω²R
4π²x R / T²
4 x 3.14²x 6.38 x 10⁶ / (6.43 x60 x 60)²
= 0.47 m /s²
If we assume also that the temperature of the air does not change, we can use Boyle's Law:
p₁V₁ = p₂V₂
Now, we know:
p₁ = 100kPa
V₂ = 100cm³ (the volume of the tyre)
V₁ = 120cm³ (becuse the air is contained inside the tyre AND the pump)
We can solve for p₂:
p₂ = (p₁V₁)/V₂
= (100×120)/100
= 120kPa
Therefore your answer is: 120kPa
The second object exerts an equal and opposite force on the first object.
Answer:
work done is = 0
Explanation:
given data
distance = 2 cm
potential = 1 V
charge with magnitude = 1 nC
to find out
work done by the electrostatic force
solution
we know that at equipotential surface is that surface which have equal potential at each every point that we say
work done will be
work done = ∫dw
∫dw =
here q is charge
so
net work done = q ( v2 - v1 )
and
so v2 = v1 = 0
so
work done is = 0
Answer:
A. 10 N
B. 20 N
C. 1,000 N
Explanation:
D. According to Newton's Third Law, in the simplest terms, each and every action (force) has an equal but opposite reaction. So when the air pushes out to the left, the pressure of the air being released propels the balloon to the right. Therefore, Newton's Third Law is followed in this scenario. That is the same case for the above three questions as well.