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3 years ago

What is the unit of density

1 answer:

3 0

Density<span> = Mass/Volume. The units for </span>density<span> are grams per cubic centimeter or grams per milliliter </span>

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How does the viscosity of a liquid affect the definition of a liquid?

yaroslaw [1]

Viscosity is another type of bulk property defined as a liquid's resistance to flow. When the intermolecular forces of attraction are strong within a liquid, there is a larger viscosity. An example of this phenomenon is imagining a race between two liquids down a windshield.

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3 years ago

Read 2 more answers

When a substance goes directly from a gaseous state to a solid state as dry ice does

Naddik [55]

Answer: Sublimation I think.

Explanation:

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3 years ago

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An archer fish spies a meal of a grasshopper sitting on a long stalk of grass at the edge of the pond in which he is swimming. I

andrew-mc [135]

Answer:

The archerfish must spit at a minimum speed of $3.43m/s$ at an angle of $69.14\°$ above the horizontal.

Explanation:

First of all, we need to find the angle above the horizontal at which the archerfish must spit, as we can see in the attachment this angle is $\Theta = 69.14\°$ .

Then we use the formula $h=\frac{v_{0}^{2}sin^{2} \Theta}{2g}$ , as we clear it for $v_{0}$ , we obtain, $v_{0}=\frac{\sqrt{2gh} }{sin\Theta}=\frac{\sqrt{2(9.8m/s^{2})(0.525m)} }{sin(69.14\°)}=3.43m/s$ , therefore the archerfish must spit at a minimum speed of $3.43m/s$ at an angle of $69.14\°$ above the horizontal.

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3 years ago

The area of the piston to the master cylinder in a hydraulic braking system of a car is 0.4 square inches. If a force of 6.4 lb

Anit [1.1K]

Answer:

The force applied on one wheel during braking = 6.8 lb

Explanation:

Area of the piston (A) = 0.4 $in^{2}$

Force applied on the piston(F) = 6.4 lb

Pressure on the piston (P) = $\frac{F}{A}$

⇒ P = $\frac{6.4}{0.4}$

⇒ P = 16 $\frac{lb}{in^{2} }$

This is the pressure inside the cylinder.

Let force applied on the brake pad = $F_{1}$

Area of the brake pad ( $A_{1}$ )= 1.7 $in^{2}$

Thus the pressure on the brake pad ( $P_{1}$ ) = $\frac{F_{1} }{A_{1} }$

When brake is applied on the vehicle the pressure on the piston is equal to pressure on the brake pad.

⇒ P = $P_{1}$

⇒ 16 = $\frac{F_{1} }{A_{1} }$

⇒ $F_{1}$ = 16 × $A_{1}$

Put the value of $A_{1}$ we get

⇒ $F_{1}$ = 16 × 1.7

⇒ $F_{1}$ = 27.2 lb

This the total force applied during braking.

The force applied on one wheel = $\frac{F_{1} }{4}$ = $\frac{27.2}{4}$ = 6.8 lb

⇒ The force applied on one wheel during braking.

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3 years ago

What is the half-life of an isotope if after 30 days you have 31.25 g remaining from a 250 g beginning sample size?

Dima020 [189]

Answer:The time required for half of the original population of radioactive atoms to decay is called the half-life. The relationship between the half-life, T1/2, and the decay constant is given by T1/2 = 0.693/λ.

Explanation:

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2 years ago