Answer:
Each part of a two-dimensional vector is known as a component. The components of a vector depict the influence of that vector in a given direction. The components of a vector depict the influence of that vector in a given direction.
Explanation:
hope this helps
Answer:
a) v = 0.8 m / s
, b)
= 0.777 m / s
, c) ΔK = 0.93 J
Explanation:
This exercise can be solved using the concepts of moment, first let's define the system as formed by the two blocks, so that the forces during the crash have been internal and the moment is conserved.
They give us the mass of block 1 (m1 = 100kg, its kinetic energy (K = 32 J), the mass of block 2 (m2 = 3.00 kg) and that it is at rest (v₀₂ = 0)
Before crash
po = m1 vo1 + m2 vo2
po = m1 vo1
After the crash
= (m1 + m2) 
a) The initial speed of the block of m1 = 100 kg, let's use the kinetic energy
K = ½ m v²
v = √2K / m
v = √ (2 32/100)
v = 0.8 m / s
b) The final speed,
p₀ =
m1 v₀1 = (m1 + m2) 
= m1 / (m1 + m2) v₀₁
The initial velocity is calculated in the previous part v₀₁ = v = 0.8 m / s
= 100 / (3 + 100) 0.8
= 0.777 m / s
c) The change in kinetic energy
Initial K₀ =
K₀ = 32 J
Final
= ½ (m1 + m2)
²
= ½ (3 + 100) 0.777²
= 31.07 J
ΔK =
- K₀
ΔK = 31.07 - 32
ΔK = -0.93 J
As it is a variation it could be given in absolute value
Part D
For this part s has the same initial kinetic energy K = 32 J, but it is block 2 (m2 = 3.00kg) in which it moves
d) we use kinetic energy
v = √ 2K / m2
v = √ (2 32/3)
v = 4.62 m / s
e) the final speed
v₀₂ = v = 4.62 m/s
p₀ = m2 v₀₂
m2 v₀₂ = (m1 + m2) 
= m2 / (m1 + m2) v₀₂
= 3 / (100 + 3) 4.62
= 0.135 m / s
f) variation of kinetic energy
= ½ (m1 + m2)
²
= ½ (3 + 100) 0.135²
= 0.9286 J
ΔK = 0.9286-32
ΔK = 31.06 J
Answer with Explanation:
Let rest mass
at point P at distance x from center of the planet, along a line connecting the centers of planet and the moon.
Mass of moon=m
Distance between the center of moon and center of planet=D
Mass of planet=M
We are given that net force on an object will be zero
a.We have to derive an expression for x in terms of m, M and D.
We know that gravitational force=
Distance of P from moon=D-x
=Force applied on rest mass due to m
=Force on rest mass due to mas M
because net force is equal to 0.





Let 
Then, 




b.We have to find the ratio R of the mass of the mass of the planet to the mass of the moon when x=
Net force is zero




Hence, the ratio R of the mass of the planet to the mass of the moon=4:1
Answer:
The answer is C. I and II only
Explanation:
Just took the test.