The density of the body and the height or the depth of the body since the formula of liquid pressure is density x height gravity
You got the formulas on the sheet on the top :) So just use those, exchanging v (as in velocity, expressed in m/s) and the d (in meters) and t (in seconds). Hope you will manage it.
U need to set up n solve the general eqn for simple harmonic motion:
x" = -(k/m)x
solution is x(t) = (x0)*cos(wt) + (v0/w)*sin(wt)
where w=sqrt(k/m), x0 is x-position at t=0 and v0 is vel at t=0
u already calculated f in Q.2 and w = 2*pi*f
x0 is 0 as it starts at eqm
v0 is given at 5.1
so u have x(t)
vel is given by x'(t) = (x0)*(-w)*sin(wt) + (v0/w)*w*cos(wt)
substitute t=0.32, x0=0, v0=5.1 n w in the above, u can solve for v at t=0.32.
Potential energy =
(mass) x (gravity) x (height above the reference level) .
Relative to the bottom of the cliff, the potential energy
at the top of the cliff is
(25kg) x (9.8 m/s²) x (30 meters)
= (25 x 9.8 x 30) kg-m²/s²
= 7,350 joules .
Kinetic energy = (1/2) x (mass) x (speed²)
The rock's kinetic energy at the bottom is
the same as its potential energy at the top.
7,350 joules = (1/2) x (25 kg) x (speed²)
Divide each side
by 12.5kg : 7,350 joules/12.5 kg = speed²
7,350 kg-m²/s² / 12.5kg = speed²
(7,350 / 12.5) m²/s² = speed²
588 m²/s² = speed²
Take the square root
of each side:
Speed = √(588 m²/s²)
= 24.248... m/s (rounded)
Answer:
a= kinetic energy vs. different masses at same speed, b= kinetic energy vs. same masses at different speeds
Explanation:
graphs are looking at speed so masses don't matter as much. same speed the whole time will equal same kinetic energy the whole time.
