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slega [8]
3 years ago
14

Select the correct answer. A ball is thrown straight down from the top of a building at a velocity of 16 ft/s. The building is 4

80 feet tall, and the acceleration due to gravity is 32 ft/s2. This problem can be represented using the following equation. How much time will the ball take to reach the ground
Physics
1 answer:
BartSMP [9]3 years ago
8 0

Answer:

The ball takes 5s to reach the ground

Explanation:

in order to solve this problem we use the kinematics equation with gravity as acceleration:

h=v_0t+1/2*gt^2

we replace the values

0=1/2*32t^2+16t-480

We solve this quadratic equation:

t=5s

t=-6s   (this solution has not physical sense)

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Two whistles blow at the same time. The first whistle has a frequency twice that of the second whistle (it is a higher pitch). W
suter [353]

Answer:

the first one

Explanation:

7 0
2 years ago
What is the scientific method​
MissTica

Answer:

Step 7- Communicate. Present/share your results. Replicate.

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Explanation:

4 0
3 years ago
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A police radar gun uses X-band microwave radiation at a frequency of 12.2 GHz. Microwaves travel at the speed of light, or 3x108
quester [9]

Answer:

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Explanation:

6 0
3 years ago
A(n) 10.1 g bullet is fired into a(n) 2.41 kg ballistic pendulum and becomes embedded in it. The acceleration of gravity is 9.8
fomenos

Answer:

v = 186.90\,\frac{m}{s}

Explanation:

The motion of ballistic pendulum is modelled by the appropriate use of the Principle of Energy Conservation:

\frac{1}{2}\cdot (m_{p}+m_{b})\cdot v^{2} = (m_{p}+m_{b})\cdot g \cdot h

The final velocity of the system formed by the ballistic pendulum and the bullet is:

v = \sqrt{2\cdot g\cdot h}

v = \sqrt{2\cdot (9.807\,\frac{m}{s^{2}} )\cdot (0.031\,m)}

v\approx 0.78\,\frac{m}{s}

Initial velocity of the bullet can be calculated from the expression derived of the Principle of Momentum:

(0.0101\,kg)\cdot v = (2.41\,kg + 0.0101\,kg)\cdot (0.78\,\frac{m}{s} )

v = 186.90\,\frac{m}{s}

5 0
2 years ago
A van de Graaff generator accelerates electrons so that they have energies equivalent to that attained by falling through a pote
Marat540 [252]

Answer:

Hello your question is incomplete hence I will give you a general answer on how A van de Graaff generator works

answer :

If the electrons falls through a PD of 150mV the electron will gain energy of   150MeV

Explanation:

when a Van de Graff generator is used to accelerate an electron through a PD ( potential difference ) of any value the particle ( electron )  the electron will gain energy  ( eV )  which is is equivalent in value of the PD it accelerated through

hence if the electrons falls through a PD of 150mV the electron will gain energy of   150MeV

4 0
2 years ago
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