Ask question

Ask question

All categories

3 years ago

15

Normal Samantha is using ribbon to make bows to be sold at a school fundraiser. She has 83.2 meters of ribbon. She needs 1.28 me

ters of ribbon for each bow. How many bows she can make?
The answer would be 65
hope that helps :b

1 answer:

adelina 88 [10]3 years ago

4 0

Answer:

83.2 meters ÷ 1.28 meters = 65 bows

You might be interested in

What is the mean price per pound for each type of produce?

IrinaK [193]

Answer:

Fruits: 107

Vegetables: 56.5

Step-by-step explanation:

Average is found by adding all of the values together and then dividing by the number of values that there are.

So for fruits, you would do 62+55+49+50+98+328 and then divide that whole thing by six.

Same for veggies, 34+122+57+21+79+26 with the answer divided by six.

6 0

3 years ago

PLEASE HELP! 90 POINTS!!!!! 4) Edward is playing a game where he draws cards with integers on them from a deck. If the integer i

My name is Ann [436]

1st card : 3 steps forward

2nd card: 3 steps back

3rd card: 4 steps back

4th card: 5 steps forward

5th card: 10 steps forward

6th card: 7 steps back

Total steps : 3 + 3 + 4 +5 +10 + 7 = 32

Answer: D) 32

4 0

3 years ago

Two factors have an estimated product of 10,000. One is a single digit. What two factors can they be. Explain your thinking

RideAnS [48]

It could be 5000 and 2, because 2 is a single digit and the product equals 10000.

5 0

3 years ago

The sum of the first two terms of an infinite GP is 6 and each term is 5 times the sum of the succeeding termsthen the second te

kozerog [31]

Answer:

$\dfrac{6}{7}$ .

Step-by-step explanation:

It is given that the sum of first two terms of an infinite GP is 6.

nth term of a GP is

$a_n=ar^{n-1}$

$a+ar=6$ ...(1)

Each term is 5 times the sum of the succeeding terms.

$a_n=5(a_{n+1}+a_{n+2}+...+\infty)$

$ar^{n-1}=5(ar^n+ar^{n+1}+...+\infty)$

$ar^{n-1}=5ar^n(1+r+r^2+...+\infty)$

Divide both sides by a.

$r^{n-1}=5r^n(\dfrac{1}{1-r})$ $[\text{Sum of infinite GP}=\dfrac{a}{1-r}]$

$\dfrac{r^n}{r}=\dfrac{5r^n}{1-r}$

$\dfrac{1}{r}=\dfrac{5}{1-r}$

$1-r=5r$

$1=6r$

$\dfrac{1}{6}=r$

The common ratio is 1/6.

Put r=1/6 in (1).

$a+a(\dfrac{1}{6})=6$

$6a+a=36$

$7a=36$

$a=\dfrac{36}{7}$

Second term $ar=\dfrac{36}{7}\times \dfrac{1}{6}=\dfrac{6}{7}$

Therefore, the second term is $\dfrac{6}{7}$ .

4 0

3 years ago

Find the length of AD

Masteriza [31]

5/x = 10/12

10x = 5•12

10x = 60

x = 60/10

x = 6

5 0

3 years ago