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Mariulka [41]
3 years ago
6

What is the mass of 3.2 moles of h2O ?

Chemistry
1 answer:
Arturiano [62]3 years ago
6 0

Answer:

\boxed{\text{57.7 g} }

Explanation:

The first step is to calculate the molar mass of H₂O:

\begin{array}{rcr}\text{2 H} & = & 2.02\\\text{1 O} & = & 16.00\\\text{TOTAL} & = & \mathbf{18.02}\\\end{array}

So, 1 mol has a mass of 18.02 g.

Next you calculate the mass of 3.2 mol of H₂O

\begin{array}{rcl}m & = & \text{3.2 mol H$_{2}$O} \times \dfrac{\text{18.02 g H$_{2}$O}}{\text{1 mol H$_{2}$O}}\\ & = &\boxed{\textbf{57.7 g H$_{2}$O}} \\\end{array}

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A nuclear waste site. cesium-137 is a particularly dangerous by-product of nuclear reactors. it has a half-life of 30 years. it
hram777 [196]
The mass decay rate is of the form
m(t) = m_{0} e^{-kt}
where
m₀ = 3000 g,the initial mass
k = the decay constant
t = time, years.

Because the half-life is 30 years, therefore
e^{-30k} =  \frac{1}{2} \\\ -30k = ln(0.5) \\ k =  \frac{ln(0.5)}{-30} =0.0231

After 60 years, the mass remaining is
m = 3000 e^{-0.0231*60} = 750 \, g

Answer: 750 g

4 0
3 years ago
Lead can be prepared from galena [lead(II) sulfide] by first roasting the galena in oxygen gas to form lead(II) oxide and sulfur
Vesna [10]

Answer:

a) Step 1:

2PbS(g)+3O_2(g)\overset{roasting}\rightarrow 2PbO(s)+2SO_2(g)

Step 2:

2PbO(s)+PbS(s)\overset{\Delta }\rightarrow 3Pb(l)+SO_2(g)

b) The overall balanced reaction for given process is ;

3PbS(s)+3O_2(g)\rightarrow 3Pb(l)+3SO_2(g)

Explanation:

a)

Galena = PbS

Lead(II) oxide = PbO

Sulfur dioxide = SO_2

Step 1:

Roasting the galena in oxygen gas to form lead(II) oxide and sulfur dioxide.

Balanced equation of step 1:

2PbS(g)+3O_2(g)\overset{roasting}\rightarrow 2PbO(s)+2SO_2(g)..[1]

Step 2:

Heating the metal oxide with more galena forms the molten metal and more sulfur dioxide.

Balanced equation of step 2:

2PbO(s)+PbS(s)\overset{\Delta }\rightarrow 3Pb(l)+SO_2(g)..[2]

b)

For over all reaction add [1] and [2]. The overall balanced reaction for given process is ;

3PbS(s)+3O_2(g)\rightarrow 3Pb(l)+3SO_2(g)

5 0
3 years ago
Read 2 more answers
Agl+Fe2(CO3)3=Fel3+Ag2CO3
Trava [24]

If you're looking for the balances equation to this the answer is

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4 0
3 years ago
Arsenic has one stable isotope:75/33 As.
algol13
The answer is 42 neutrons
6 0
3 years ago
How many mL of a 0.193 M aqueous solution of ammonium bromide, , must be taken to obtain 8.42 grams of the salt?
PilotLPTM [1.2K]

Answer:

445 mL NH₄Br

Explanation:

(Step 1)

Convert grams ammonium bromide (NH₄Br) to moles using its molar mass.

Molar Mass (NH₄Br): 14.007 g/mol + 4(1.008 g/mol) + 79.904 g/mol

Molar Mass (NH₄Br): 97.943 g/mol

8.42 grams NH₄Br                1 mole
-----------------------------  x  ------------------------  =  0.0860 moles NH₄Br
                                         97.943 grams

(Step 2)

Calculate the volume of NH₄Br using the molarity equation. Then, convert liters (L) to milliliters (mL).

Molarity (M) = moles / volume (L)

0.193 M = 0.0860 moles / volume

(0.193 M) x volume = 0.0860 moles

volume = 0.445 L

1,000 mL = 1 L

0.445 L NH₄Br           1,000 mL
------------------------  x  ------------------  =  445 mL NH₄Br
                                        1 L

8 0
2 years ago
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