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GrogVix [38]
2 years ago
6

**PLEASE HELP** If you were presented with a preserved brain specimen, but weren’t told whether it was from a human or a sheep,

how would you determine which animal it was from? Describe at least three differences you would use to help determine your answer.
Chemistry
1 answer:
Gemiola [76]2 years ago
3 0

Answer:

size-humans brains are usually larger than animals, shape-some animal brains are shaped very odd, and the cerebrum-that is the part of the brain that makes us human.

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Which quantity is constant when working with boyles, charles, and gay lussacs law?
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boyles law states that the volumes of a gas will decrease as pressure increases if the temperature remains constant.

charles law states that the volume of a gas will increase as temp increases if the pressure remains constant.

gay-lussacs law states that the pressure increases as temp increases if the volume remains constant.

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According to the cup wall diagrams, why does the double wall vacuum
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Crack is manufactured by using _________________________ to remove hydrochlorides to create a crystaline form of cocaine that ca
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Answer:Sodium Bicarbonate

Explanation:Crack is manufactured by using Sodium Bicarbonate (NaHCO3) to remove hydrochlorides to create a crystalline form of cocaine that can be smoked.

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If 21.3 grams of lithium react with excess water, how many liters of hydrogen gas can be produced at 297 Kelvin and 1.40 atmosph
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Hope it helped you.

4 0
3 years ago
Determine the resulting pH when 12mL if 0.16M HCl are reacted with 32 mL if 0.24M KOH.
TEA [102]

Answer:

pH = 13.1

Explanation:

Hello there!

In this case, according to the given information, we can set up the following equation:

HCl+KOH\rightarrow KCl+H_2O

Thus, since there is 1:1 mole ratio of HCl to KOH, we can find the reacting moles as follows:

n_{HCl}=0.012L*0.16mol/L=0.00192mol\\\\n_{KOH}=0.032L*0.24mol/L=0.00768mol

Thus, since there are less moles of HCl, we calculate the remaining moles of KOH as follows:

n_{KOH}=0.00768mol-0.00192mol=0.00576mol

And the resulting concentration of KOH and OH ions as this is a strong base:

[KOH]=[OH^-]=\frac{0.00576mol}{0.012L+0.032L}=0.131M

And the resulting pH is:

pH=14+log(0.131)\\\\pH=13.1

Regards!

3 0
2 years ago
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