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GrogVix [38]
3 years ago
6

**PLEASE HELP** If you were presented with a preserved brain specimen, but weren’t told whether it was from a human or a sheep,

how would you determine which animal it was from? Describe at least three differences you would use to help determine your answer.
Chemistry
1 answer:
Gemiola [76]3 years ago
3 0

Answer:

size-humans brains are usually larger than animals, shape-some animal brains are shaped very odd, and the cerebrum-that is the part of the brain that makes us human.

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The electron configuration of an element is shown below.
gayaneshka [121]

Answer:it is in group 7

Explanation:it is in this group because in the increasing number of atomic number the element is found in group seven. The element is likely to receive 3 electrons while bonding with another element to make it stable.

5 0
3 years ago
Read 2 more answers
Draw the major organic product for the reaction of 1-phenylpropan-1-one with the provided phosphonium ylide.
prohojiy [21]

Answer:

2-methylene propylbenzene

Explanation:

The Wittig Reaction is a reaction that converts aldehydes and ketones into alkenes through reaction with a phosphorus ylide.

The ketone in this case is 1-phenylpropan-1-one. The provided phosphonium ylide is shown in the image attached. The reaction involves;

i) alkylation  

ii) addition

The product of the major organic product of the reaction is 2-methylene propylbenzene.

4 0
3 years ago
What general rule can be followed when choosing a type of solvent for a particular solute
ehidna [41]
General 'rule' - "like dissolves like". The solubility of a solute in a solvent (that is, the extent of the mixing of the solute and solvent species) depends on a balance between the natural tendency for the solute and solvent species to mix and the tendency for a system to have the lowest energy possible.

Hope this helps :p
4 0
3 years ago
The diameter of a biscuit is approximately 51 millimeters (mm). An atom of bismuth (Bi) is approximately 320. picometers (pm) in
astraxan [27]

Answer:

1.5e+8 atoms of Bismuth.

Explanation:

We need to calculate the <em>ratio</em> of the diameter of a biscuit respect to the diameter of the atom of bismuth (Bi):

\\ \frac{diameter\;biscuit}{diameter\;atom(Bi)}

For this, it is necessary to know the values in meters for any of these diameters:

\\ 1m = 10^{3}mm = 1e+3mm

\\ 1m = 10^{12}pm = 1e+12pm

Having all this information, we can proceed to calculate the diameters for the biscuit and the atom in meters.

<h3>Diameter of an atom of Bismuth(Bi) in meters</h3>

1 atom of Bismuth = 320pm in diameter.

\\ 320pm*\frac{1m}{10^{12}pm} = 3.20*10^{-10}m

<h3>Diameter of a biscuit in meters</h3>

\\ 51mm*\frac{1}{10^{3}mm} = 51*10^{-3}m = 5.1*10^{-2}m

<h3>Resulting Ratio</h3>

How many times is the diameter of an atom of Bismuth contained in the diameter of the biscuit? The answer is the ratio described above, that is, the ratio of the diameter of the biscuit respect to the diameter of the atom of Bismuth:

\\ Ratio_{\frac{biscuit}{atom}}= \frac{5.1*10^{-2}m}{3.20*10^{-10}m}

\\ Ratio_{\frac{biscuit}{atom}}= \frac{5.1}{3.20}\frac{10^{-2}}{10^{-10}}\frac{m}{m}

\\ Ratio_{\frac{biscuit}{atom}}= \frac{5.1}{3.20}\frac{10^{-2}}{10^{-10}}\frac{m}{m}

\\ Ratio_{\frac{biscuit}{atom}}= 1.5*10^{-2+10}

\\ Ratio_{\frac{biscuit}{atom}}= 1.5*10^{8}=1.5e+8

In other words, there are 1.5e+8 diameters of atoms of Bismuth in the diameter of the biscuit in question or simply, it is needed to put 1.5e+8 atoms of Bismuth to span the diameter of a biscuit in a line.

6 0
3 years ago
Which of the following is an example of radiation?
Lapatulllka [165]
I believe the best answer to that question wud be D. I cud b wrong 
5 0
3 years ago
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