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gregori [183]
2 years ago
10

What is Kb for N2H4 if the pH of a 0.158M solution of N2H5Cl is 4.5?

Chemistry
1 answer:
olasank [31]2 years ago
3 0

Answer:

Kb= 1.58 * 10^{-6}

Explanation:

The correct question is

What is Kb for N2H4 if the pH of a 0.158M solution of N2H5Cl is 4.5?

Solution-

N2H4Cl hydrolyses on addition of water

The reaction equation is as follows -

N2H4+ + H2O ----> N2H4 + H3O+

Ka = \frac{K_w}{K_b} = \frac{10^{-14}}{K_b}

pH = 4.5

[H+] = 10^{-pH} = 10^{-4.5}

K_b=  \frac{10^{-14} }{K_b} =  \frac{Y_2}{0.158}  \\K_b= \frac{(10^{-4.5})^2}{0.158}\\=> Kb = 0.158 * 10-14 /(10-4.5)2

 Kb= 1.58 * 10^{-6}

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Ivahew [28]

Answer:

B. 8

Explanation:

because I learned that in 6th

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3 years ago
Write the chemical formula for the anion present in the aqueous solution of Pb(C2H3O2)2
yKpoI14uk [10]

Pb(C₂H₃O₂)₂ is lead(II) acetate

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The chemical formula for the anion present in the aqueous solution of Pb(C₂H₃O₂)₂ is C₂H₃O₂²⁻

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3 0
2 years ago
Read 2 more answers
What mass will 33.6 l of chlorine gas (cl2) have at stp
Aloiza [94]
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volume of gas/ number of mol=  22.4l/mol
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5 0
2 years ago
Balance 6Sb +6Cl2– 6SbCl3
labwork [276]

<u>Answer:</u>

<u>Balancin</u>g is making the number of atoms of each element same on both the sides  (reactant and product side).

To find the number of atoms of each element we multiply coefficient and the subscript  

For example 5 Ca_1 Cl_2 contains

5 × 1 = 5,Ca atoms and

5 × 2 = 10, Cl atoms

If there is a bracket in the chemical formula

For example 3Ca_3 (P_1 O_4 )_2 we multiply coefficient \times subscript \times number outside the bracket.......... to find the number of atoms  

(Please note: 3 is the coefficient, and if there is no number given then 1 will be the coefficient )

So

3 × 3 = 9, Ca atoms  

3 × 1 × 2 = 6, P atoms  

3 × 4 × 2 = 24, O atoms are present.

So

Let us balance the equation given

1Sb +1Cl_2 > 1SbCl_3

(Unbalanced)

Reactant side - Number of atoms of each element - Product side

1  - Sb - 1

2 - Cl - 3  

So we have on the product side odd number of Cl to convert to even number, multiply SbCl_3 by 2

The equation changes to

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Reactant side - Number of atoms of each element - Product side

1  - Sb - 2

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Multiplying Sb by 2 and Cl_2

2Sb +3Cl_2> 2SbCl_3

The equation is balanced now!!!!  

Reactant side - Number of atoms of each element - Product side

2  - Sb - 2

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Balanced.

4 0
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V125BC [204]

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The solutions that are most likely acids are those that turn blue litmus red <em>and </em>do not evoke a color change in red litmus. A solution that turns red litmus blue <em>or </em>does not evoke a color change in blue litmus is likely not an acid. Using these criteria, solutions 4 and 7 are most likely acids since they both turn blue litmus red (and they cause no color change in red litmus).

The correct answer choice would thus be D.

4 0
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