Answer:
357 g of the transition metal are present in 630 grams of the compound of the transition metal and iodine
Explanation:
In any sample of the compound, the percentage by mass of the transition metal is 56.7%. This means that for a 100 g sample of the compound, 56.7 g is the metal while the remaining mass, 43.3 g is iodine.
Given mass of sample compound = 630 g
Calculating the mass of iodine present involves multiplying the percentage by mass composition of the metal by the mass of the given sample;
56.7 % = 56.7/100 = 0.567
Mass of transition metal = 0.567 * 630 = 357.21 g
Therefore, the mass of the transition metal present in 630 g of the compound is approximately 357 g
The hybrid orbital of this molecule is 
. Hence, option C is correct.
<h3>What is hybridisation?</h3>
Hybridization is defined as the concept of mixing two atomic orbitals to give rise to a new type of hybridized orbitals.
In this compound, a hybrid orbital makes I-O bonds. Due to hybridization iodate should have tetrahedral geometry but because of the presence of lone pair of electrons the shape of 
the ion is pyramidal.
The hybrid orbital of this molecule is . Hence, option C is correct.
Learn more about hybridisation here:
brainly.com/question/23038117
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Answer:
This question sadly does not make much sense, please rephrase it.
The volume of the flask would simply be equal to the
volume of the water. And the mass of the water would be the difference after
and before weigh.
mass of water = 489.1 g – 241.3 g
mass of water = 247.8 g
Therefore the volume of water (which is also the volume
of the flask) is:
volume = 247.8 g / (1.00 g/cm^3)
volume = 247.8 cm^3
The total mass of the flash when filled with chloroform
would be:
total mass with chloroform = 241.3 g + 247.8 cm^3 (1.48
g/cm3)
total mass with chloroform = 608.04 g
Answers:
volume = 247.8 cm^3
total mass with chloroform = 608.04 g
Answer:
Sodium hydroxide reacts with iron(III) chloride to produce iron(III) hydroxide and sodium chloride.
Hope this helps plz hit the crown :D
