What will be the coordinates of point A if figure ABCD is reflected across the x-axis?

2(x-8) + 4x = 6(x - 2) - 4

mrs_skeptik [129]

0=0, all numbers are solutions

5 0

3 years ago

Read 2 more answers

Can someone please help me with this

Readme [11.4K]

Answer:

7) 28.8 in

8) 80.6 mm

9) 68.3 cm

(All answers to the nearest tenth)

Step-by-step explanation:

7) The traingle is a right-angled triangle since the 4 angles of a rectangle are right angles.

Applying Pythagoras' Theorem,

x²= 16² +24²

x²= 832

x= √832

x= 28.8 in (nearest tenth)

8) Applying Pythagoras' Theorem,

x² +40²= 90²

x²= 8100 -1600

x²= 6500

x= 80.6 mm (nearest tenth)

9) See the attached picture for better understanding.

1st picture shows the simplified diagram of the question, indicating where line x lies in the rectangular prism.

Now, if we cut the prism into half diagonally so that we obtain 2 equal triangular prism, we would obtain 2 prisms that look like the one drawn in picture 2.

Now zoom in to the blue face of the prism, we would get a triangle as shown in picture 3.

Let's find the value of y.

Applying Pythagoras' Theorem,

y²= 40² +54²

y²= 4516

y= √4516

Look at picture 2 again at focus at the pink shaded triangle. It has been re-drawn in picture 4.

Now we know that y= √4516.

Applying Pythagoras' Theorem,

x²= (√4515)² +12²

x²= 4660

x= √4660

x= 68.3 cm (nearest tenth)

3 0

2 years ago

20 Points + Brainliest for the answer and Explanation!!!

Vlad1618 [11]

Answer:

$P+Q=5x^2+4$

$Q-P=-x^2-4x+16$

Step-by-step explanation:

We are given

$P=3x^2+2x-6$

$Q=2x^2-2x+10$

Calculation of P+Q:

$P+Q=3x^2+2x-6+2x^2-2x+10$

now, we can combine like terms

$P+Q=3x^2+2x^2+2x-2x+10-6$

$P+Q=5x^2+0+4$

$P+Q=5x^2+4$

Calculation of Q-P:

$Q-P=2x^2-2x+10-(3x^2+2x-6)$

Firstly, we will distribute negative sign

$Q-P=2x^2-2x+10-3x^2-2x+6$

now, we can combine like terms

$Q-P=2x^2-3x^2-2x-2x+6+10$

$Q-P=-x^2-4x+16$

8 0

2 years ago

11th grade geometry:

Aliun [14]

Answer:

The perimeter is 72 units and the area is 149 square units.

Step-by-step explanation:

$\triangle SBA$ has coordinates $S(15,-8),B(-2,21)$ and $A(0,0)$

Using the distance formula.........

Length of side $SB = \sqrt{(15+2)^2+(-8-21)^2}= \sqrt{17^2+(-29)^2}= \sqrt{1130}$

Length of side $BA= \sqrt{(-2)^2+(21)^2}= \sqrt{445}$

Length of side $AS =\sqrt{(15)^2+(-8)^2}=\sqrt{289}=17$

So, the perimeter of the triangle will be: $(SB+BA+AS)= \sqrt{1130}+ \sqrt{445}+17 =71.71... \approx 72$ units. (Rounded to the nearest unit)

The height of the triangle for the corresponding base $SB$ is 8.89 units.

Formula for the Area of triangle, $A= \frac{1}{2}(base\times height)$

So, the area of the $\triangle SBA$ will be: $\frac{1}{2}(\sqrt{1130}\times 8.89)= 149.42... \approx 149$ square units. (Rounded to the nearest unit)

3 0

3 years ago

Find the area under the standard normal probability distribution between the following pairs of z-scores. a. z=0 and z=3.00 e.

prohojiy [21]

Answer:

a. P(0 < z < 3.00) = 0.4987

b. P(0 < z < 1.00) = 0.3414

c. P(0 < z < 2.00) = 0.4773

d. P(0 < z < 0.79) = 0.2852

e. P(-3.00 < z < 0) = 0.4987

f. P(-1.00 < z < 0) = 0.3414

g. P(-1.58 < z < 0) = 0.4429

h. P(-0.79 < z < 0) = 0.2852

Step-by-step explanation:

Find the area under the standard normal probability distribution between the following pairs of z-scores.

a. z=0 and z=3.00