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GenaCL600 [577]
2 years ago
12

What will be the coordinates of point A if figure ABCD is reflected across the x-axis?​

Mathematics
1 answer:
egoroff_w [7]2 years ago
7 0
The coordinate for point A is (-2,5)
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2(x-8) + 4x = 6(x - 2) - 4
mrs_skeptik [129]
0=0, all numbers are solutions
5 0
3 years ago
Read 2 more answers
Can someone please help me with this ​
Readme [11.4K]

Answer:

7) 28.8 in

8) 80.6 mm

9) 68.3 cm

(All answers to the nearest tenth)

Step-by-step explanation:

7) The traingle is a right-angled triangle since the 4 angles of a rectangle are right angles.

Applying Pythagoras' Theorem,

x²= 16² +24²

x²= 832

x= √832

x= 28.8 in (nearest tenth)

8) Applying Pythagoras' Theorem,

x² +40²= 90²

x²= 8100 -1600

x²= 6500

x= 80.6 mm (nearest tenth)

9) See the attached picture for better understanding.

1st picture shows the simplified diagram of the question, indicating where line x lies in the rectangular prism.

Now, if we cut the prism into half diagonally so that we obtain 2 equal triangular prism, we would obtain 2 prisms that look like the one drawn in picture 2.

Now zoom in to the blue face of the prism, we would get a triangle as shown in picture 3.

Let's find the value of y.

Applying Pythagoras' Theorem,

y²= 40² +54²

y²= 4516

y= √4516

Look at picture 2 again at focus at the pink shaded triangle. It has been re-drawn in picture 4.

Now we know that y= √4516.

Applying Pythagoras' Theorem,

x²= (√4515)² +12²

x²= 4660

x= √4660

x= 68.3 cm (nearest tenth)

3 0
2 years ago
20 Points + Brainliest for the answer and Explanation!!!
Vlad1618 [11]

Answer:

P+Q=5x^2+4

Q-P=-x^2-4x+16

Step-by-step explanation:

We are given

P=3x^2+2x-6

Q=2x^2-2x+10

Calculation of P+Q:

P+Q=3x^2+2x-6+2x^2-2x+10

now, we can combine like terms

P+Q=3x^2+2x^2+2x-2x+10-6

P+Q=5x^2+0+4

P+Q=5x^2+4

Calculation of Q-P:

Q-P=2x^2-2x+10-(3x^2+2x-6)

Firstly, we will distribute negative sign

Q-P=2x^2-2x+10-3x^2-2x+6

now, we can combine like terms

Q-P=2x^2-3x^2-2x-2x+6+10

Q-P=-x^2-4x+16

8 0
2 years ago
11th grade geometry:
Aliun [14]

Answer:

<em>The perimeter is 72 units and the area is 149 square units.</em>

Step-by-step explanation:

\triangle SBA has coordinates S(15,-8),B(-2,21) and A(0,0)

Using the distance formula.........

Length of side SB = \sqrt{(15+2)^2+(-8-21)^2}= \sqrt{17^2+(-29)^2}= \sqrt{1130}

Length of side BA= \sqrt{(-2)^2+(21)^2}= \sqrt{445}

Length of side AS =\sqrt{(15)^2+(-8)^2}=\sqrt{289}=17

So, the perimeter of the triangle will be:  (SB+BA+AS)= \sqrt{1130}+ \sqrt{445}+17 =71.71... \approx 72 units.   <em>(Rounded to the nearest unit)</em>

The height of the triangle for the corresponding base SB is 8.89 units.

<u>Formula for the Area of triangle</u>,  A= \frac{1}{2}(base\times height)

So, the area of the \triangle SBA will be:  \frac{1}{2}(\sqrt{1130}\times 8.89)= 149.42... \approx 149 square units.   <em>(Rounded to the nearest unit)</em>

3 0
3 years ago
Find the area under the standard normal probability distribution between the following pairs of​ z-scores. a. z=0 and z=3.00 e.
prohojiy [21]

Answer:

a. P(0 < z < 3.00) =  0.4987

b. P(0 < z < 1.00) =  0.3414

c. P(0 < z < 2.00) = 0.4773

d. P(0 < z < 0.79) = 0.2852

e. P(-3.00 < z < 0) = 0.4987

f. P(-1.00 < z < 0) = 0.3414

g. P(-1.58 < z < 0) = 0.4429

h. P(-0.79 < z < 0) = 0.2852

Step-by-step explanation:

Find the area under the standard normal probability distribution between the following pairs of​ z-scores.

a. z=0 and z=3.00

From the standard normal distribution tables,

P(Z< 0) = 0.5  and P (Z< 3.00) = 0.9987

Thus;

P(0 < z < 3.00) = 0.9987 - 0.5

P(0 < z < 3.00) =  0.4987

b. b. z=0 and z=1.00

From the standard normal distribution tables,

P(Z< 0) = 0.5  and P (Z< 1.00) = 0.8414

Thus;

P(0 < z < 1.00) = 0.8414 - 0.5

P(0 < z < 1.00) =  0.3414

c. z=0 and z=2.00

From the standard normal distribution tables,

P(Z< 0) = 0.5  and P (Z< 2.00) = 0.9773

Thus;

P(0 < z < 2.00) = 0.9773 - 0.5

P(0 < z < 2.00) = 0.4773

d.  z=0 and z=0.79

From the standard normal distribution tables,

P(Z< 0) = 0.5  and P (Z< 0.79) = 0.7852

Thus;

P(0 < z < 0.79) = 0.7852- 0.5

P(0 < z < 0.79) = 0.2852

e. z=−3.00 and z=0

From the standard normal distribution tables,

P(Z< -3.00) = 0.0014  and P(Z< 0) = 0.5

Thus;

P(-3.00 < z < 0 ) = 0.5 - 0.0013

P(-3.00 < z < 0) = 0.4987

f. z=−1.00 and z=0

From the standard normal distribution tables,

P(Z< -1.00) = 0.1587  and P(Z< 0) = 0.5

Thus;

P(-1.00 < z < 0 ) = 0.5 -  0.1586

P(-1.00 < z < 0) = 0.3414

g. z=−1.58 and z=0

From the standard normal distribution tables,

P(Z< -1.58) = 0.0571  and P(Z< 0) = 0.5

Thus;

P(-1.58 < z < 0 ) = 0.5 -  0.0571

P(-1.58 < z < 0) = 0.4429

h. z=−0.79 and z=0

From the standard normal distribution tables,

P(Z< -0.79) = 0.2148  and P(Z< 0) = 0.5

Thus;

P(-0.79 < z < 0 ) = 0.5 -  0.2148

P(-0.79 < z < 0) = 0.2852

8 0
2 years ago
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