What is a vector?

Physics

2 answers:

Anon25 [30]3 years ago

8 0

Answer:

B. a quantity that has magnitude and direction

Nonamiya [84]3 years ago

7 0

A quantity that has magnitude and direction.

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When you are in the front passenger seat of a car turning to the left, you may find yourself pressed against the right-side door

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When you are in the front passenger seat of a car turning to the left, you may find yourself pressed against the right-side door. because of <span> Newton's first and third law</span>

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3 years ago

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rodikova [14]

Answer:

Explanation:

The legend of King Arthur is well-known in literature. Based on Unsolved Mysteries of History, there is little to suggest it is true. Do you think it is important for people to believe in legends like King Arthur even if there is little evidence to support them? Why or why not? Write a short (3 paragraphs) explanatory essay stating your opinion. Justify your opinion and conclusions with relevant textual evidence (quotes or paraphrased ideas from sources) and background knowledge. Remember to use relevant vocabulary from the text in your essay.l

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3 years ago

In a simulation on earth, an astronaut in his space suit climbs up a vertical ladder. On the moon, the same astronaut makes the

mr Goodwill [35]

Answer:

Gravitational potential energy of the astronaut will change by a greater amount on the earth

Explanation:

Gravitational potential energy is expressed by the formula;

GPE = mgh

This means that the gravitational potential energy is directly proportional to the gravity(g)

Now, from constant values, gravity of moon is 1.62 m/s² while gravity of the earth is 9.81 m/s².

This means that if we plug in the values of g on the earth and g on the moon, the potential energy on the earth would be greater than that of the moon

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3 years ago

You throw a rock straight up from the edge of a cliff. It leaves your hand at time t = 0 moving at 13.0 m/s. Air resistance can

Zarrin [17]

Answer:

0.36s, 2.3s

Explanation:

Let gravitational acceleration g = 9.81 m/s2. And let the throwing point as the ground 0 for the upward motion. The equation of motion for the rock leaving your hand can be written as the following:

$s = v_0t + gt^2/2$

where s = 4 m is the position at 4m above your hand. $v_0 = 13 m/s$ is the initial speed of the rock when it leaves your hand. g = -9.81m/s2 is the deceleration because it's in the downward direction. And t it the time(s) it take to get to 4m, which we are looking for