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dolphi86 [110]
3 years ago
12

A load of 45N attached to a spring that is hanging vertically stretches the spring 0.14m. What is the spring constant?

Physics
1 answer:
Vesna [10]3 years ago
6 0
6.3 That Would be the I answer I think but Check on Google For the formula
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A 40-cmcm-long tube has a 40-cmcm-long insert that can be pulled in and out. A vibrating tuning fork is held next to the tube. A
Licemer1 [7]

Answer:

1070 Hz

Explanation:

First, I should point out there might be a typo in the question or the question has inconsistent values. If the tube is 40 cm long, standing waves cannot be produced at 42.5 cm and 58.5 cm lengths. I assume the length is more than the value in the question then. Under this assumption, we proceed as below:

The insert in the tube creates a closed pipe with one end open and the other closed. For a closed pipe, the difference between successive resonances is a half wavelength \frac{\lambda}{2}.

Hence, we have

\dfrac{\lambda}{2}=58.5-42.5=16 \text{ cm}

\lambda=32\text{ cm}=0.32 \text{ m}.

The speed of a wave is the product of its wavelength and its frequency.

v=f\lambda

f=\dfrac{v}{\lambda}

f=\dfrac{343}{0.32}=1070 \text{ Hz}

7 0
3 years ago
At noon on a clear day, sunlight reaches the earth\'s surface at Madison, Wisconsin, with an average intensity of approximately
Dmitrij [34]

Intensity of sunlight at given position is defined as power received per unit area

so here we can say

I = 2 kJ/s*m^2

area  on which photons are received is given as

A = 4.80 cm^2 = 4.80 * 10^-4 m^2

now we can find the power received due to sunlight

P = I*A

P = 2* 10^3 * 4.80 * 10^-4

P = 0.96 Watt

now we can say this power is due to photons that strikes on surface of earth

so here we can say

P = N\frac{hc}{\lambda}

given here that

\lambda = 510 nm

0.96 = N\frac{6.6 * 10^{-34}* 3 * 10^8}{510*10^{-9}}

0.96 = N * 3.88 * 10^{-19}

N = \frac{0.96}{3.88*10^{-19}}

N = 2.47 * 10^{18}

so it will strike 2.47 * 10^18 photons on given area per second

3 0
3 years ago
Planet X is in a stable circular orbit around a star, as shown in the figure. Which of the following graphs best predicts the an
damaskus [11]

Answer:

C

Explanation:

Angular momentum is the product of moment of inertia and angular velocity.

L = I × ω

Since the planet follows a stable circular orbit, I and ω are constant and non-zero.  Therefore, the angular momentum is constant and non-zero.

5 0
3 years ago
An object has a starting velocity of 20 m/s. If it accelerates at a rate of 2 m/s' for 3 seconds,
Ghella [55]

Answer:

26 m/s

69 m

Explanation:

Given:

v₀ = 20 m/s

a = 2 m/s²

t = 3 s

Find: v and Δx

v = at + v₀

v = (2 m/s²) (3 s) + 20 m/s

v = 26 m/s

Δx = v₀ t + ½ at²

Δx = (20 m/s) (3 s) + ½ (2 m/s²) (3 s)²

Δx = 69 m

3 0
3 years ago
An aminoacyl-trna that enters the a site of the ribosome will next occupy which site?
kkurt [141]

Answer:

The P site

Explanation:

After the formation of peptide linkage, the trna of P site becomes free, more to the E site and then slip away. The A site trna has dipeptide instead of a single aminoacid.

In the prescence of translocase and energy from GTP, the ribosome move in such a way the peptidyl bearing trna of A site come to lie with P sit. This exposes next codon to A site. A new aminoacid trna complex reaches the fresh codon exposed at A site.

5 0
3 years ago
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