Simply divide your wire by 12 and cut off the excess (as it cannot make a full 12-inch section).
27
÷12=2
So you have two 12-inch sections and an additional 3.4-inch section.
Answer:
=========================
<h2>Given </h2>
Triangle with:
- Base of n² -3,
- Midsegment of 39.
<h2>To find</h2>
<h2>Solution</h2>
As per definition of midsegment, it is connecting the midpoints of two sides and its length is half the length of the opposite side of the triangle.
So we have:
Solve it for n:
- n² - 3 = 78
- n² = 81
- n = √81
- n = 9
Correct choice is D.
from the diagram, we can see that the height or line perpendicular to the parallel sides is 8.5.
likewise we can see that the parallel sides or "bases" are 24.3 and 9.7, so
![\textit{area of a trapezoid}\\\\ A=\cfrac{h(a+b)}{2}~~ \begin{cases} h=height\\ a,b=\stackrel{parallel~sides}{bases}\\[-0.5em] \hrulefill\\ h=8.5\\ a=24.3\\ b=9.7 \end{cases}\implies \begin{array}{llll} A=\cfrac{8.5(24.3+9.7)}{2}\\\\ A=\cfrac{8.5(34)}{2}\implies A=144.5~in^2 \end{array}](https://tex.z-dn.net/?f=%5Ctextit%7Barea%20of%20a%20trapezoid%7D%5C%5C%5C%5C%20A%3D%5Ccfrac%7Bh%28a%2Bb%29%7D%7B2%7D~~%20%5Cbegin%7Bcases%7D%20h%3Dheight%5C%5C%20a%2Cb%3D%5Cstackrel%7Bparallel~sides%7D%7Bbases%7D%5C%5C%5B-0.5em%5D%20%5Chrulefill%5C%5C%20h%3D8.5%5C%5C%20a%3D24.3%5C%5C%20b%3D9.7%20%5Cend%7Bcases%7D%5Cimplies%20%5Cbegin%7Barray%7D%7Bllll%7D%20A%3D%5Ccfrac%7B8.5%2824.3%2B9.7%29%7D%7B2%7D%5C%5C%5C%5C%20A%3D%5Ccfrac%7B8.5%2834%29%7D%7B2%7D%5Cimplies%20A%3D144.5~in%5E2%20%5Cend%7Barray%7D)
<u>Answer:</u>
c= -1/2
<u>Step-by-step explanation:</u>
Let's solve your equation step-by-step.
4
/3 = −6c −
5/
3
Step 1: Simplify both sides of the equation.
4
/3 =−6c + −5
/3
Step 2: Flip the equation.
−6c + −5
/3 = 4/3
Step 3: Add 5/3 to both sides.
−6c + −5
/3 + 5
/3 = 4/3 + 5
/3 −6c
=3
Step 4: Divide both sides by -6.
−6c −6 = 3
− 6
c = −1
/2
Answer: proly like 2
Step-by-step explanation:
Because you have to pay and scan!
