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ivanzaharov [21]
2 years ago
10

Write all of the complex numbers that are graphed

Mathematics
2 answers:
algol [13]2 years ago
5 0

Answer:

A : (-2) + (3)i

B : (-1) + (1)i

C : (3) + (-4)i

D : (4) + (1)i

Step-by-step explanation:

In the graph attached,

Real part of a complex number is plotted on x-axis and imaginary part of the complex number on y-axis.

Therefore, in any ordered pair (x, y)

x → Real part of the complex number

y → Imaginary part of the complex number

Complex numbers are,

A : (-2) + (3)i

B : (-1) + (1)i

C : (3) + (-4)i

D : (4) + (1)i

Artist 52 [7]2 years ago
5 0

Answer:

A : (-2) + (3)i

B : (-1) + (-1)i

C : (3) + (-4)i

D : (4) + (1)i

Step-by-step explanation:

Just took it. Edg 2020. Hope this helps :)

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One container is filled with mixture that is 25% acid. A second container is filled with a mixture that is 55% acid. The second
algol13

Answer:

Therefore the third container contains   \frac{735}{17}\% = 43.23 %  acid.

Step-by-step explanation:

Given that, One container is filled with the mixture that 25% acid. 55% acid is contain by second container.

Let the volume of first container be x cubic unit.

Since the volume of second container is 55% larger than the first.

Then the volume of the second container is

= (V\times \frac{100+55}{100})   cubic unit.

=\frac{155}{100}V  cubic unit.

The amount of acid in first container is

=V\times \frac{25}{100}  cubic unit.

=\frac{25}{100}V  cubic unit.

The amount of acid in second container is

=(\frac{155}{100}V \times \frac{55}{100}) cubic unit.

=\frac{8525}{10000}V cubic unit.

Total amount of acid =(\frac{25}{100}V+\frac{8525}{10000}V) cubic unit.

                                   =(\frac{2500+8525}{10000}V) cubic unit.

                                   =(\frac{11025}{10000}V)cubic unit.

Total volume of mixture =(V+\frac{155}{100}V) cubic unit.

                                       =\frac{100+155}{100}V cubic unit.

                                       =\frac{255}{100}V  cubic unit.

The amount of acid in the mixture is

=\frac{\textrm{The volume of acid}}{\textrm{The amount of mixture}}\times 100 \%

=\frac {\frac{11025}{10000}V}{\frac{255}{100}V}\times 100\%

=\frac{735}{17}\%

Therefore the third container contains  \frac{735}{17}\%  acid.

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Step-by-step explanation:

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Which expression can be used to approximate the expression below, for all positive numbers a, b, and x, where a Not-equals 1 and
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The expression that can be used to approximate the expression below islog_a x = \frac{log_{b}a}{log_{b}x}

  • Given the logarithmic function expressed as log_a x, we need the log expression that is equivalent to the given expression.

  • To do this, we will write the logarithm as a quotient to the same base. Using the base of 10, the expression can be written as;

log_a x = \frac{log_{10}a}{log_{10}x}

This is similar to the option c where the base of "b" was used as log_a x = \frac{log_{b}a}{log_{b}x}

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Step-by-step explanation:

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