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3 years ago

Each person attending a two-day conference receives 4 meal vouchers to use.

1 answer:

6 0

Part A: Let x and y be the number of persons attending the two-day conference and y be the number of vouchers released. The equation that would best express the given is,
y = 4x

Part B: The number of people attending the conference is determined by dividing the given number of vouchers by 4. The answer is 956.

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HELP Asap :-/!!!! AHHHHHHHHHHH

pychu [463]

Answer:

x = 9

Step-by-step explanation:

If ΔMNO ≅ ΔPST, their corresponding sides must also be ≅(congruent).

NO is corresponds to TS, thus sides NO and side TS are ≅.

=> 20 = 3x - 7

=> 3x = 27

=> x = 9

6 0

2 years ago

Please help fast i am struggling

klemol [59]

B is the correct answer for your question I do believe, I hope that helped you. If not I am sorry, I tried to answer fast for you.

6 0

2 years ago

What is the volume of 10 2 in 5.5in

svetlana [45]

Answer:

110 in³

Step-by-step explanation:

The volume of a rectangular prism is the product of its dimensions:

V = LWH

V = (10 in)(2 in)(5.5 in) = 110 in³

5 0

2 years ago

A welder requires 18 hours to do a job. After the welder and an apprentice work on a job for 6 hours, the welder moves to anothe

Dafna1 [17]

Answer:

the apprentice can complete the job in 30 hours by working alone.

Step-by-step explanation:

Given:

Number of hours required to complete a job by welder = 18 hours

Number of hours welder work on job = 6 hours.

Number of hours required by apprentice to complete the job = 14 hours

We need to find Number of hours required to complete a job by apprentice alone.

Solution:

Let Number of hours required to complete a job by apprentice alone be 'a'.

Also let the job completed be = 1

Now we know that ;

Time required on job is equal to sum of Number of hours welder work on job and Number of hours required by apprentice to complete the job.

framing in equation form we get

Time required on job = $6+14 =20\ hrs$

Now we can say that;

each has done a fraction of the work so we will add to two fraction as number of hours of work done by Total number of hours required to do the work to complete 1 job.

so we can frame the equation as;

$\frac{6}{18}+\frac{20}{a}=1$

By reducing the fraction we get;

$\frac{1}{3}+\frac{20}{a}=1$

Now we will make the denominator common to solve the fraction we get;

$\frac{1\times a}{3\times a}+\frac{20\times3}{a\times3}=1\\\\\frac{a}{3a}+\frac{60}{3a}=1$

Now denominators are same so we will solve the numerator we get;

$\frac{a+60}{3a}=1$

Multiplying both side by 3a we get;

$\frac{a+60}{3a}\times3a=1\times 3a\\\\a+60=3a$

Combining the like terms we get;

$3a-a=60\\\\2a=60$

Dividing both side by 2 we get;

$\frac{2a}{2}=\frac{60}{2}\\\\a=30\ hrs$

Hence the apprentice can complete the job in 30 hours by working alone.

4 0

2 years ago

true or false If x represents a random variable with mean 114 and standard deviation 40, then the standard deviation of the samp

Goshia [24]

Answer:

$\mu = 114, \sigma = 40$

We also know that we select a sample size of n =100 and on this case since the sample size is higher than 30 we can apply the central limit theorem and the distribution for the sample mean would be given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

And the standard deviation for the sampling distribution would be:

$\sigma_{\bar X}= \frac{40}{\sqrt{100}}= 4$

So then the answer is TRUE

Step-by-step explanation:

Let X the random variable of interest and we know that the true mean and deviation for this case are given by:

$\mu = 114, \sigma = 40$

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

And the standard deviation for the sampling distribution would be:

$\sigma_{\bar X}= \frac{40}{\sqrt{100}}= 4$

So then the answer is TRUE

6 0

3 years ago