- The control group defined as a group that does not include any change to the inconstant being tested. Why is a control crucial in an experiment? The control group is crucial because it acts as a benchmark to variatethe results of the experiment to. The experimental group is the group that the scientist is examing . The experimental group receives a change to a variable, or the conditions allowed to change in the experiment.
- There are two types of control group : Positive control groups and Negative control groups
- The positive control group is a group that is contrive to produce the effect you are looking for in the experimental group. The positive control group shows the scientists that the craved results are achievable . This helps stop false negative outcome in the experimental group, where a negative result is receive but is due to a failure in the experiment instead than a truly negative result based on the experimental conditions.
- A negative control group is a group that is not exposed to the different scientist is testing, called the independent variable. A negative control group function as a benchmark to secure that the results that are got are actually due to the independent variable and not anything else
To know more about control group visit :
brainly.com/question/14308149
#SPJ9
Answer:
The correct option is FALSE
Explanation:
Mole ratio is the ratio of the number of moles of two compounds in a balanced chemical reaction. Number of moles of a compound in a chemical reaction is the number written before the compound.
For example, the mole ratio of Iron (Fe) and water (H₂O) in the equation below is 3:4
3Fe + 4H₂O ⇒ Fe₃O₄ + 4H₂
Thus, mole ratio does not compare subscripts of compounds.
Answer:
Q = 3.21 kJ
Explanation:
First, with the heat of hydration and the lattice energy, we can actually calculate the difference between those two to get the heat evolved per mole. In this case it would be:
657 - 639 = 18 kJ/mol
Now, the expression to get the heat is:
Q = m*ΔE
We already have the energy, now we need to get the moles of the cesium chloride.
The molar mass of cesium chloride is 168.36 g/mol, so the moles:
mole = 30/168.36 = 0.1781 moles
Finally the heat:
Q = 0.1781 * 18
Q = 3.21 kJ
65ml x 1.3 molar = 0.0845 moles solution #1
0.0845 moles / .208 L = 0.4 M
0.4M × 104 ml / 213 ml = .20 M after sig figs
