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Answer: 3.72 M
Explanation:
Expression for rate law for first order kinetics is given by:
where,
k = rate constant =
t = age of sample = 15.0 minutes
a = let initial amount of the reactant = 10.0 M
a - x = amount left after decay process = ?
The concentration of in a solution after 15.0 minutes have passed is 3.72 M
Answer:
<h2>6 m/s</h2>Explanation:
The speed of the man can be found by using the formula
d is the distance
t is the time taken
From the question we have
We have the final answer as
<h3>6 m/s</h3>Hope this helps you
Answer:
1. 25 moles water.
2. 41.2 grams of sodium hydroxide.
3. 0.25 grams of sugar.
4. 340.6 grams of ammonia.
5. 4.5x10²³ molecules of sulfur dioxide.
Explanation:
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In this case, since the mole-mass-particles relationships are studied by considering the Avogadro's number for the formula units and the molar mass for the mass of one mole of substance, we proceed as shown below:
1. Here, we use the Avogadro's number to obtain the moles in the given molecules of water:
2. Here, since the molar mass of NaOH is 40.00 g/mol, we obtain:
3. Here, since the molar mass of C6H12O6 is 180.15 g/mol:
4. Here, since the molar mass of ammonia is 17.03 g/mol:
5. Here, since the molar mass of SO2 is 64.06 g/mol:
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