Question

Between 10 P.M. and 7:54 A.M.​, the water level in a swimming pool decreased by 11/40 . Assuming that the water level decreased at a constant​ rate, how much did the water level drop each​ hour?

Answer 1

Answer:

It approximately dropped 0.027777 per hour.

Step-by-step explanation:

First, we calculate the decrease.

Decrease = 11/40 = 0.275

Then,  we calculate the time interval.

From 10 pm to 7:54 hours will be 9.54 hours

Time interval= (9 + 54/60) hours

Time interval=9.9 hours

Finally, we calculate how much it dropped each hour

0.275/9.9 ≈ 0.027777

So it approximately dropped 0.027777 per hour.

Answer 2

Answer:

7:54 A.M to 10 P.M is = 14 hrs and 6 mins

60 mins = 1 hour

therefore 6 mins = 0.1 hour

14 hrs plus 0.1 hrs = 14.1 hours

if 14.1 hrs = 11/40

1 HR = x

cross multiply

14.1x = 11/40

divide both sides by 14.1

14.1x / 14.1 = 11/40 / 14.1

X = 11/564 or 0.0195 times every hour